Calculate TKPH Ratings for Mining Trucks Using VIMS Data: A Beginner's Guide

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Discussion Overview

The discussion revolves around calculating the TKPH (ton-kilometer per hour) ratings for mining trucks using data from VIMS (Vehicle Information Management System). Participants are exploring the methodology for determining mean tire load and the associated calculations, including weight distribution and average wheel load, in the context of a specific set of data.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant presents initial calculations for TKPH ratings based on provided data, questioning the validity of their results.
  • Another participant clarifies the calculation of mean tire load, emphasizing the need to consider the weight distribution across the tires and the number of tires.
  • A third participant seeks clarification on the weight distribution calculations for loaded conditions, specifically how certain values were derived from the total weight.
  • Participants discuss the importance of using the correct weight distribution percentages to arrive at accurate mean tire load values.

Areas of Agreement / Disagreement

There is no consensus on the correct method for calculating TKPH ratings, as participants express differing views on the calculations and the assumptions made regarding weight distribution.

Contextual Notes

Participants highlight the need for specific vehicle information, such as weight distribution and tire configuration, which may not be fully addressed in the discussion. There are also unresolved questions regarding the accuracy of certain calculations presented.

knightza
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I've just started a research on the tyre of mining trucks and am a bit unsure on how to calculate the TKPH ratings.

Say for this set of data from VIMS,

GMW = 390 tons
Payload = 245.1 tons
Total cycle time = 15:29 minutes
Total cycle distance = 6.8 km

And that is one shift.

So, mean tyre load = 390 + 245.1/2 = 512.55 tons
AWSS = (6.8*1)/(15.5/60)

TKPH rating = mean tyre load * AWSS > 13000 ton-kilometer per hour which is REALLY big.

Can anyone see what I did wrong?
 
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Mean Tire Load=(tire load empty+tire load loaded)/2
So GMW=390 that's vehicle loaded
Payload=245.1 that's the load, SO Empty vehicle=390-245=145
Then you have to obtain your vehicle information about weight disturibtion and number of wheels to get each tire load.
Like for example--2 front tires and 4 rear tires with distribution...
Empty Loaded
Front% 55% 35%
Rear% 45% 65%
front 39.87 53.63 ---mean tire load ...46.75
rear 16.31 63.37 ---mean tire load ...39.84


AWSS=6.8/(15.5/60)=26.3226
TKPH=MTL*AWSS
front =46.75*26.3226 = 1230
rear =39.84*26.3226 = 1048
THATS TOO some high as distance=6.8 km and low time 15.5 for the whole cycle,and sure big payload 245.
GOOD LUCK
 
Mean Tire Load=(tire load empty+tire load loaded)/2
So GMW=390 that's vehicle loaded

THE BELOW PASTED TREAD, NEED CLARFICATION.
ON LOADED CONDITION HOW IS THE LOAD DISCTRBUTION CALCULATED
EG ( 390*65%)/4= 63.37 BUT ON THE FRONT
(390*35%)/2=68.25,( IT HAS BEEN MENTIONED AS 53.63) HOW IT SI ARRIVED
PLEASE CLARFY AS I HAVE TO WORK ON CERTAIN TKPH CALUALTION.

CBC




Payload=245.1 that's the load, SO Empty vehicle=390-245=145
Then you have to obtain your vehicle information about weight disturibtion and number of wheels to get each tire load.
Like for example--2 front tires and 4 rear tires with distribution...
Empty Loaded
Front% 55% 35%
Rear% 45% 65%
front 39.87 53.63 ---mean tire load ...46.75
rear 16.31 63.37 ---mean tire load ...39.84


AWSS=6.8/(15.5/60)=26.3226
TKPH=MTL*AWSS
front =46.75*26.3226 = 1230
 
it is mistake, use the weight distribution% mentioned
 

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