Calculate velocity when time is equal

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1. Ball is thrown at an object that is 12m away and 8m above the initial height of the ball. At what velocity must the ball be thrown to hit the object?
2. V=d/t
3. You can find the angle at which the ball must be thrown by using tan^-1= (8/12)= 33.69 degrees, not sure if that helps much. Vx=12m/t, vy=8m/t, so at what velocity will the time be equal? Do i have enough info...?
 
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Vx=12mxt, vy=8mxt,

v = d/t. How did you write the above equations? The angle also not correct.

It is a projectile motion.

You have to consider the components of velocity along the horizontal and vertical direction. Then use the kinematic equations for horizontal and vertical displacement.
 
yes, ok so for the horizontal velocity its velocity horizontal=displacement horizontal / time. then for velocity vertical = displacement vertical / time, what do i do next?
 
First of all go through the projectile motion from any site or textbook. Learn the basic things. Then I will help you.
 
Ok, i know the basics but i just do not know what to do with so few givens. How can i find the velocity without time and vice versa?