Calculate Volume of Hydrogen Needed to Hydrogenate 50g Trans-Carveol

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Discussion Overview

The discussion revolves around calculating the volume of hydrogen gas required to hydrogenate 50g of trans-carveol at standard temperature and pressure (STP). Participants explore the application of the ideal gas law and the stoichiometry involved in the hydrogenation process.

Discussion Character

  • Homework-related, Mathematical reasoning, Technical explanation

Main Points Raised

  • One participant calculates the moles of trans-carveol to be 0.329 and uses the ideal gas law to find a volume of 815L for hydrogen gas.
  • Another participant points out that 1 mole of gas at STP occupies 22.4 L, suggesting that the initial calculation of volume is incorrect and should be less than 22.4 L.
  • A participant acknowledges a potential error in the gas constant used in their calculations, suggesting a correction to 0.08315.
  • There is a discussion about whether to double the volume of hydrogen needed due to the presence of two double bonds in trans-carveol, with one participant agreeing with this approach but noting it does not guarantee correctness.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the correct volume of hydrogen needed, as there are competing views regarding the calculations and the application of stoichiometry.

Contextual Notes

Participants express uncertainty regarding the correct application of the ideal gas law and the appropriate gas constant, as well as the implications of the double bonds in the hydrogenation process.

Who May Find This Useful

Students or individuals interested in organic chemistry, particularly in reactions involving hydrogenation and gas laws.

schoolboy10
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Homework Statement


Calculate the volume required to hydrogenate 50g of trans-carveol at STP.


Homework Equations


PV=nRT
m=152g

The Attempt at a Solution



I think I might have this one but just for clarification if I'm missing something. The amount of moles is 0.329 using the amount of carveol given and the molecular mass. So plugging in:

V=(0.329)(8.315)(298)/1
= 815L

Now, there are two double bonds in trans-carveol, so we need double the amount of hydrogen to hydrogenate the double bonds. So would it just be 815L x 2 = 1630L needed?
 
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1 mole of gas at STP occupies 22.4 L, you have calculated there is 0.329 moles of carveol, that means you need LESS than 22.4 L, not many times more.

You are making an obvious error. Check your units.
 
Oh, silly me, it would be 0.08315, correct?
 
Ahh I see, thank you. So after I do the calculations to find the volume, was I right in saying originally that you double the volume since there are two double bonds?
 
That would be my approach, it doesn't make it automatically right.
 

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