Calculating a Bijective Function: f(N0)

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SUMMARY

The function f: x ∈ Q → (5x-7)/6 is established as bijective. The calculated values for f(N0) include f(0) = -7/6, f(1) = -1/3, f(2) = 1/2, and f(3) = 4/3. To generalize the set that includes the image of f(N0), it is confirmed that the denominator remains constant at 6, while the numerator can take on values defined by the expression 5N - 7 for N in the natural numbers.

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Hi, i have this function f : x \in Q \rightarrow (5x-7)/6
the function is bijective now i need to calculate:
f(N0)
i get :
f(0)=-7/6, f(1)=-1/3, f(2)=1/2, f(3)=4/3, etc...
I need to generalize the set that include the image of f(N0),
but i don't know what could be.
 
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Let's not simplify the fraction. Then the denominator will always be 6. What can the numerator be?
 

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