Calculating Acceleration and Tension in a Pulley System with Inclined Planes

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Homework Help Overview

The discussion revolves around a physics problem involving a pulley system with two blocks, one on an inclined plane and the other hanging vertically. The original poster seeks to calculate the acceleration of the blocks and the tension in the rope connecting them.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the application of Newton's second law and the need for free body diagrams. There are attempts to clarify the original poster's calculations and definitions of variables used in their equations.

Discussion Status

Some participants have provided guidance on how to approach the problem, suggesting the need for clearer definitions and steps in the calculations. There is ongoing exploration of the correct values and methods to find both acceleration and tension, with participants questioning assumptions and previous calculations.

Contextual Notes

There are indications of confusion regarding the values used in calculations, particularly concerning trigonometric functions related to the angle of the incline. The original poster expresses uncertainty about their results, and there are references to images that may aid in understanding the problem setup.

komarxian
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Homework Statement


Block A has a mass of 75 kg and is initially at rest on a frictionless inclined plane tilted at a 37 ° above the horizon. Block A is attached to a massless rope that is connected to the top of Block B by way of a massless frictionless pulley. Block B also has a mass of 75 kg and hangs vertically. Find the acceleration of the blocks. Also find the Tension, T, in the rope.

Homework Equations

The Attempt at a Solution


When I solved it I found that a = 4 m/s^2, but I think I got it wrong. I used a=(mg-Fparallel)/B, but I may/most likely screwed up here. Any help would be greatly appreciated ;D. I also think that the acceleration might be 0, because it says that it is initially at rest, but that answer also doesn't feel right.
Thank you!
 
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Draw a picture. Include free body diagrams.

Express Newton's second law for each object.

Solve for a.
 
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komarxian said:
I used a=(mg-Fparallel)/B,
You appear to think that adequately explains to others what you did. I assure you it doesn't. E.g. what do you mean by Fparallel? How did you calculate it? What does B represent in the equation - the mass of block B? What about m?
Please post all your steps and define your variables.
 
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Okay, I tried this.
image.jpeg
 
komarxian said:
Mass A is M and mass B is m
That looks fine. You are also asked for the tension.
 
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haruspex said:
That looks fine. You are also asked for the tension.
So do you know if my answer is correct? Thank you for the help!
 
komarxian said:
So do you know if my answer is correct? Thank you for the help!
Yes, I agree with your answer.
 
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Okay thanks! Will start on the tension now.
 
  • #10
ImageUploadedByPhysics Forums1452209167.311935.jpg
ImageUploadedByPhysics Forums1452209193.244202.jpg

Okay, now that I have the acceleration, I was wondering If what I did to get tension was correct? My teacher recomended using the equation that I used in the second image.
 
  • #11
Im sorry but I am pretty sure a is -1.99 ms^-2. i'l put some pics up in a sec
 
  • #12
WrongMan said:
Im sorry but I am pretty sure a is -1.99 ms^-2. i'l put some pics up in a sec
You're right, I didn't notice komarxian had sin and cos mixed up.
 
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  • #13
Oh darn, I'll take a look at that. @wrongedMan some pics would help a ton! Thank you for the help @haruspex as well
 
  • #14
well without wanting to give it all away :p ... start with that (img), you should try and solve it without inputing any values just find an expression for a then put values in, repeat for T (bit more tricky for T). I'll still be around for a couple of hours to help you out if you get stuck :)edit1: BTW, important bit: sin(37) is NOT 4/5 maybe that was your mistake
edit2: yep that was your mistake

edit 3: ah @haruspex i see that's what you meant, i thought you meant he actually wrote cos instead of sin not that he got the values mixed up
 

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  • #15
! Thank you! I misread my formula sheet (again) omo.
 

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