Calculating Acceleration of a Space Shuttle in Zero-Gravity Conditions

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Homework Help Overview

The discussion revolves around calculating the acceleration of a space shuttle operating in zero-gravity conditions, given its thrust and weight on Earth. The subject area includes concepts of force, mass, and acceleration as described by Newton's laws of motion.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between weight and mass, with some attempting to calculate mass from the given weight using the equation W=mg. Others explore how to apply the thrust to find acceleration using F=ma.

Discussion Status

Several participants have offered guidance on the correct approach to find mass and subsequently acceleration. There is ongoing clarification regarding the use of units and the distinction between weight and force. Multiple interpretations of the calculations are being explored, with some participants expressing confusion and seeking further assistance.

Contextual Notes

Participants note the importance of unit consistency, particularly distinguishing between Newtons and kilograms. There is also mention of the problem's context being similar to textbook examples, which may influence understanding.

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When the space shuttle is flying in space, away from the influence of any gravitational fields, its engines provide a total thrust of 2.4 X 10^7 N. If the shuttle weighs 2.0 X 10^7 N on the surface of the earth, what is its acceleration? (use g=10 m/s^2)

Fg= (2.0 X 10^7 N)(10 m/s^2)
= 2.0 X 10^8 N m/s^2

Fnet= (2.0 X 10^8 N m/s^2)-(2.4 X 10^7 N)
= 1.76 X 10^8 N m/s^2

a= 1.76 X 10^8

I have absolutely no clue how to do this but this is what I have figured out can someone please explain for me?
 
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If the shuttle WEIGHS 2 x 10^7 N on earth, then this is the force.

What you need to calculate is the mass of the shuttle using F = mg

The question states that it is away from the influence of any gravitational fields, so the net force is given by the thrust.

Using F = ma you can then determine the acceleration.
 
I'm sorry but I still don't understand.

so the mass of the shuttle would be 2 x 10^8 N then?
and Fnet= 2.4 X10^7?
 
hey, lol this looks awefully similar to a problem i have in my textbook.. but anyway
its like how he said, u have to remember that mass doesn't change, weight does. So in earth, you are given a weight. Therefore, you can find the mass of the shuttle. you see

W=mg (use 10 for your g), then once you have that..use F(thrust)= ma

simple heh
 
mass of the shuttle is in KG, and force is in NEWTONS (N), it is important to get the units right..
 
OK... If something weighs 2 x 10^7 N, then this is the force with which gravity is pulling it towards Earth.

Its mass can be determined from a rearrangement of F= mg (mass is measured in kg)

Now, if we have a mass shooting through space, being pushed by an engine with a force of 2.4 x 10^7 N, we can figure out its acceleration using a rearrangement of F = ma.


Note that these are two different cases, so the F in each is different.
 
right, use W=mg, because well its not wrong technically, but weight is a force, and in physics you generally use W for weight instead of Fg. anyway tell me what u get
 
and remember the mass doesn't change
 
I think my head is all goofed up today I just can't seem to do math correctly haa..

So I would then take,
2.4 X 10^7 N = (2.0 X 10^8 N)(a)
-2.0 X 10^8 N -2.0 X 10^8 N
-1.76 X 10^8 N = a??
 
  • #10
lol, atleast you realized that is wrong.. but look acceleration is (m/s^2) force is (kg m/s^2) aka: mass x acceleration. anyway lol
2.0x10^7 N= mg (10=g)
then take that mass
2.4x10^7N=ma (a is what you solving for) if i do anything more, i will end up solving the problem
 
  • #11
Not quite.

Your 2.0 x 10^8 is wrong.

W = mg

2.0 x 10^7 = m (10)

m=?

then use F(thrust) = ma
 
  • #12
okay so then...
2.0 X 10^7 = m(10)
-10 -10
1.9 X 10^7 = m

2.4 X 10^7 N = 1.9 X 10^7(a)
-1.9X10^7N -1.9X10^7N

5.0 X 10^6 N = a
 
  • #13
You are subtracting where you need to divide. - do the calculations again.

Other than that it looks ok.

Also, remember your units! acceleration is measured in m/s^2
 
  • #14
LOL! sorry, not to be mean, but that was funny
 
  • #15
alright so. For the 8th try haha! 2.4 X 10^7 N = 1.9 X 10^7 N a
then I divide 2.4 X 10^7 N by 1.9 X 10 ^7 N and get a
so a = 1.3 m/s^2
 
  • #16
nope.. i don't know what to say lol,
 
  • #17
okay so then...
2.0 X 10^7 = m(10)
-10 -10 (ERROR)-- fix that
1.9 X 10^7 = m (fix that)

2.4 X 10^7 N = 1.9 X 10^7 (fix that) (a)
-1.9X10^7N -1.9X10^7N (DIVIDE not multiply) 6=2x3 --> 3=6/2 or 2=6/3 (6-3 doesn't = 2-3)

5.0 X 10^6 N = a
 
  • #18
Thanks a lot for the help guys. I appreciate it!
 
  • #19
alright I think I figured it out now I hope to the lord.

2.0 X 10^7 N = m(10)
------------ -------
10 10

m= 2.0 X 10^6 N

2.4 X 10^7N = 2.0 X 10^6 N a
------------- ---------------
2.0X10^6N 2.0X10^6N

a= 12 m/s^2
 
  • #20
good lol :)
 
  • #21
finally! thank you so much for your patience and your help guys.
 
  • #22
alright I think I figured it out now I hope to the lord.

2.0 X 10^7 N = m(10)
------------ -------
10 10

m= 2.0 X 10^6 N (should be Kg) just saying because if u are writing this problem down, i don't want you to get points off for that.

2.4 X 10^7N = 2.0 X 10^6 N a
------------- ---------------
2.0X10^6N 2.0X10^6N

a= 12 m/s^2
 
  • #23
okay thank you.
 

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