Calculating Air Speed & Water Height in Straws

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Homework Help Overview

The discussion revolves around calculating the speed of air in a straw and the resulting height of water in a second vertical straw when air is directed horizontally across it. The subject area includes fluid dynamics and applications of Bernoulli's equation.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the application of Bernoulli's equation to relate the air velocity and pressure changes in the straws. There are attempts to calculate the height of water based on pressure differences, with varying results and uncertainties about the assumptions made.

Discussion Status

The discussion is ongoing, with participants sharing their calculations and questioning the assumptions related to pressure at the top of the straw. Some guidance has been offered regarding the use of Bernoulli's equation, but there is no consensus on the correct approach or results yet.

Contextual Notes

Participants are working under the constraints of a homework assignment, which may limit the information available for calculations. There are also discrepancies in the expected versus calculated heights of water, indicating potential misunderstandings or misapplications of the principles involved.

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Homework Statement


Tests of lung capacity show that adults are able to exhale 1.5 liters of air through their mouths in as little as 1.0 seconds. a)if a person blows air at this rate through a drinking straw with a diameter of 0.60 cm, what is the speed of air in the straw? b) if the air from the straw in part (a) is directer horizontally across the upper end of a second straw that is vertical in water, to what height does water rise in the vertical straw.


Homework Equations





The Attempt at a Solution


i have found the answer to part (a) and it is 53 m/s and it is correct. however, i have no idea how to approach b. any help would be great.
 
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i think you need to use Bernoulli's eqn. The velocity of the airstream across the other straw will reduce the ambient pressure.
 
i tried that, but I am not sure exactly how it works. i got something like 140 cm when the answer is 19 cm.
 
Perhaps if you showed your work, we could give you a hand...
 
for a) i got the radius of straw r=.003 m
area and 1.5 L is .0015 m^3. Divide cubic meters by area of straw, and got 53.1 m/s

But for part b) How do you use Bernoulli's eqn? Do you assume the pressure at the top of the straw is appoxamately zero, since the air is being blown off?
 
When I assume that, I get a little over 10 meters... and that can't be right.
 
No, Bernoulli's law connects the speed of air across the straw with the pressure. Use Bernoulli's law to calculate the pressure.
 
so do I use the equation twice?
101.3 kPa = Pressure + (.5*1.29*53*53)

Pressure = 99488 Pascals

and then plug that in using water's density as rho the next time?
 
I got the difference in pressure as being 1812 Pacals.

so that equals 1000kg/m3 * 9.8 m/s * delta h ?

the height is .1848 meters?
 
  • #10
That doesn't make sense still.
 

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