Calculating Altitude of a Geosynchronous Satellite Orbiting Jupiter

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Homework Help Overview

The discussion revolves around calculating the altitude of a geosynchronous satellite orbiting Jupiter, which requires understanding the relationship between orbital mechanics and the properties of Jupiter, such as its mass and radius.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the use of various equations related to orbital motion, including the relationship between tangential velocity, angular velocity, and gravitational force. There is an exploration of the correct method to find the radius of the orbit and subsequent altitude.

Discussion Status

Some participants have provided guidance on the calculations and the importance of correctly interpreting the results, such as the need to subtract Jupiter's radius from the calculated orbital radius. There is also clarification regarding the units of mass used in the calculations.

Contextual Notes

Participants are navigating through the complexities of the problem, including the conversion of units and the implications of the calculations on the final altitude result. The original poster expresses uncertainty about their approach and the correctness of their calculations.

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Homework Statement



A synchronous satellite, which always remains above the same point on a planet's equator, is put in orbit around Jupiter to study that planet's famous red spot. Jupiter rotates once every 9.84 h. Use the following data to find the altitude of the satellite above the surface of the planet. Jupiter has a mass of 1.90 \cdot 10^{27}~kg, and a mean radius of 6.99 \cdot 10^{7}~m.


Homework Equations


v= \large \sqrt{ \frac{GM_j}{R_j + h}} M_j mass of Jupiter; R_j average radius of Jupiter.

v= \large \sqrt{ \frac{GM_j}{r}}

v_{tan}=r\omega

The Attempt at a Solution



I know that in order for the satellite to continually be suspended above the same spot on Jupiter, they have to be rotating through the same angles and take the amount of time to rotate through those angles. Hence, \omega_j=\omega_s= \frac{2\pi}{35424~s} (I converted the hours to seconds).

I thought of using the first forumula; but when I substituted
v_{tan}=r\omega and tried to solve for r, it became rather difficult. And so, I opted to use the second equation and perform the same steps. I solved for r, r= (\large \frac{GM_j}{\omega^2})^{1/3}

After the final substitution, r= 1.59 \cdot 10^8 m. This, however, isn't the correct answer. What did I do wrong?
 
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Bashyboy said:
And so, I opted to use the second equation and perform the same steps. I solved for r, r= (\large \frac{GM_j}{\omega^2})^{1/3}

After the final substitution, r= 1.59 \cdot 10^8 m. This, however, isn't the correct answer. What did I do wrong?
You solved for r. What altitude does that correspond to?
 
Oh, I need to subtract the average radius from the value of r I found. Also, I just noticed that the mass of Jupiter was given in kg, should I have converted it into grams?
 
Bashyboy said:
Oh, I need to subtract the average radius from the value of r I found.
Right.
Also, I just noticed that the mass of Jupiter was given in kg, should I have converted it into grams?
No. Kg is the standard unit for mass.
 
You are asked about the altitude above the surface of Jupiter.
 
I got the proper answer. Thanks be to you both.
 

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