Calculating Amount of H2SO4 Needed to Neutralize NaOH

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Discussion Overview

The discussion revolves around calculating the amount of sulfuric acid (H2SO4) needed to neutralize a specified amount of sodium hydroxide (NaOH), with references to hydrochloric acid (HCl) for comparison. The scope includes chemical reaction equations and stoichiometry related to acid-base neutralization.

Discussion Character

  • Homework-related
  • Technical explanation
  • Mathematical reasoning

Main Points Raised

  • Participants discuss the reaction equations for HCl and NaOH, and H2SO4 and NaOH.
  • One participant proposes the reaction equation: 2 NaOH + H2SO4 → Na2SO4 + 2 H2O, questioning if this is the final answer.
  • Another participant emphasizes the need to determine the amount of H2SO4 required, not just the reaction equation.
  • There is a debate over the stoichiometric relationship, with some participants suggesting that 0.5 moles of sulfuric acid are needed for 1 mole of NaOH, while others challenge this interpretation.
  • One participant notes that sulfuric acid has two acidic protons, which influences the stoichiometry of the reaction.
  • There is confusion regarding the significance of the data provided, particularly the reference to HCl and its relevance to the problem at hand.

Areas of Agreement / Disagreement

Participants express differing views on the stoichiometric coefficients and the amount of sulfuric acid required, indicating that there is no consensus on the final answer. The discussion remains unresolved regarding the interpretation of the reaction and the calculations involved.

Contextual Notes

Participants have not fully resolved the implications of the stoichiometric coefficients in the reaction equations, and there are uncertainties regarding the relevance of the information provided about HCl.

chawki
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Homework Statement


To completely neutralise 1 mol, i.e. 40.0 g, of sodium hydroxide (NaOH),
1 mol, i.e. 36.5 g, of hydrochloric acid (HCl) is required. Determine the amount (using the units
mol and gram) of sulphuric acid (H2SO4) required to neutralise the same amount of sodium
hydroxide.

Homework Equations


Write the equation for this reaction.

The Attempt at a Solution


I really have no idea what they are talking about.
 
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As told - start with the reaction equations. How does HCl react with NaOH? How does H2SO4 react with NaOH?
 
Hello Borek.

After some research, i found that the reaction should be like this:
2 NaOH + H2SO4 -------> Na2SO4 + 2 H2O.

However is this the final answer ? i don't get why they gave information on HCl and NaOH
 
chawki said:
However is this the final answer ?

How can it be the final answer, have you read the question? You are asked to determine the amount, reaction equation is not the amount of the substance.

I asked you to write TWO reaction equations.
 
The first reaction is
NaOH + HCl ---------> NaCl + H2O
 
OK. In fact this reaction is not necessary to solve the problem, but it nicely shows how acid base reactions are related - they produce salt and water. Compare both reactions to see what I am talking about.

Now concentrate on the first reaction - the one between NaOH and H2SO4. Do you know how to read the reaction equation? Can you tell how many moles of sulfuric acid reacts with ONE mole of NaOH?
 
one mole.
 
No. Look at stoichiometric coefficients.
 
0.5mole
 
  • #10
still convinced it's 0.5 mol
 
  • #11
Good for you.
 
  • #12
so that's the answer :bugeye: ?
0,5 mol of sulphuric acid ?
 
  • #13
Yes, sulfuric acid has two acidic protons, so it reacts 1:2 with NaOH.
 
  • #14
that's very surprising..i wasn't expecting this small answer..and i was expecting more complicated things since they gave us many data :bugeye:

the whole answer to this exercise is just the equation:
2 NaOH + H2SO4 ----> Na2SO4 + 2 H2O

and the amount of H2SO4 is 0.5 mol ?
by the way, what do they mean by ''same amount of NaOH''
 
  • #15
Same amount of NaOH - identical amount of NaOH, just like 40g that reacted with HCl.
 

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