Titration Calculation of Unknown Solution

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SUMMARY

The discussion centers on calculating the moles of an unknown substance through titration using Sodium Hydroxide (NaOH) and Hydrochloric Acid (HCl). The user titrated 250 cm³ of 0.1 M NaOH and utilized 17 cm³ of HCl to reach neutralization. The correct approach involves applying the formula: moles = concentration × volume, which simplifies the calculation of the unknown substance's moles. A reference link to a titration calculation resource was provided for further clarity.

PREREQUISITES
  • Understanding of titration principles
  • Familiarity with molarity and concentration calculations
  • Basic algebra skills for manipulating equations
  • Knowledge of acid-base neutralization reactions
NEXT STEPS
  • Study the concept of molarity and its applications in titration
  • Learn how to balance chemical equations for acid-base reactions
  • Explore the use of titration curves in determining equivalence points
  • Review the provided resource on titration calculations at titrations.info
USEFUL FOR

Chemistry students, laboratory technicians, and educators involved in teaching titration methods and calculations.

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Homework Statement


I titrated an unknown sample with a Sodium Hydroxide 250cm3 with 0.1M Concentration. I titrate and used up 17 cm3 using a Hydrochloric Acid to neutralise the NaOH. I have to find out the Mole of the unknown substance

Homework Equations



I forgot the equations of titration, all I can find on the internet I can't understand them.. >.<

The Attempt at a Solution



I used the 0.1 mol dm-3 NaOH and got 19.3cm3 HCl , that would be equal to 0.83 M,
 
Last edited:
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i find the easiest way of remembering the equation is to think of a triangle:
mol
concentration * volume

so mol = concentration * volume
concentration = mol/volume
volume = mol/concentration
 

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