20,0ml of 0,150M Zn(NO3)2 are mixed with 20,0ml of 1,00 x10^-4(adsbygoogle = window.adsbygoogle || []).push({});

M Na2S. Calculate the amount of milligrams of

ZnS (s) that will precipitate. (Ksp = 1,6 x10^-24

M^2 )

a) 2,68mg

b) 0,347mg

c) 4,85mg

d) 0,194mg

There are zero examples in my textbook or notes that deal with calculating theamountof precipitate that will form. Can someone help?

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# Calculating amount of precipitate that will form

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