MHB Calculating Amount of Pure Acid Needed for Desired Solution

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A chemist needs a 30% acid solution. How much pure acid needs to be mixed with 5 milliliter a of a 10% acid solution to obtain the desired solution?

The words PURE ACID for some reason or another point to 100 percent.

My equation:

0.30(x) + 0.10(5) = (x + 5)

Is this right?
 
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What you want, where x is the amount of pure acid added in mL:

0.10(5) + x = 0.50(x + 5)
 
MarkFL said:
What you want, where x is the amount of pure acid added in mL:

0.10(5) + x = 0.50(x + 5)

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