MHB Calculating Amount of Pure Acid Needed for Desired Solution

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To create a 30% acid solution from a 10% solution, the chemist needs to determine the amount of pure acid to mix with 5 milliliters of the 10% solution. The correct equation is 0.30(x + 5) = 0.10(5) + x, where x represents the volume of pure acid in milliliters. This equation balances the concentration of acid in the final solution. The discussion highlights the challenge of translating word problems into mathematical equations, emphasizing its importance in practical applications. Mastering this skill is crucial for success in various fields, including finance.
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A chemist needs a 30% acid solution. How much pure acid needs to be mixed with 5 milliliter a of a 10% acid solution to obtain the desired solution?

The words PURE ACID for some reason or another point to 100 percent.

My equation:

0.30(x) + 0.10(5) = (x + 5)

Is this right?
 
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What you want, where x is the amount of pure acid added in mL:

0.10(5) + x = 0.50(x + 5)
 
MarkFL said:
What you want, where x is the amount of pure acid added in mL:

0.10(5) + x = 0.50(x + 5)

One of my greatest struggles in math is to create an equation(s) from the words in applications. It is clearly the most important, in my opinion, math skill to learn. I vividly recall getting rejected for a Financial Advisor job in 2006 because I simply could not pass the bank test, which consisted mostly of word problems. The F. A. job could have changed my finances for the better. I took this test (and other exams) after earning my B.A. degree in 1994.
 
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