Calculating Angular Diameter of an Orbit Using Kepler's Law

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To calculate the angular diameter of an orbit using Kepler's law, it's essential to first determine the radius of the orbit, not just the distance to the observer. The distance "d" refers to how far the star and black hole system is from the observer, rather than the radius of the orbit. The period of the orbit is relevant for calculating the radius using Kepler's law, which involves the gravitational constant and the mass of the black hole. Once the radius of the orbit is established, the angular diameter can be calculated using the appropriate formulas. Understanding these relationships is crucial for accurate calculations.
Kynsuo
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Homework Statement
A star orbits a black hole at the centre of a galaxy. Assuming these orbits are circular and that the distance to the centre of the galaxy is ##d##, find the angular diameter of an orbit who's period is ##T##.
Relevant Equations
I have the radius of the black hole ##R##, the mass of the black hole ##M##.
I am confused because the question implies that I need to do some sort of calculation with Kepler's law. I got
##r+d = \sqrt[3]{\frac{T^2 GM}{4 \pi^2} } ##

But don't understand why I need this, since I already have the distance and the angular diameter should be ##\arctan (2R/d)## I think I am missing something.
 
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Kynsuo said:
But don't understand why I need this, since I already have the distance and the angular diameter should be ##\arctan (2R/d)## I think I am missing something.
You need the radius of the orbit, not the radius of the black hole.
 
Doc Al said:
You need the radius of the orbit, not the radius of the black hole.
Thanks DocAI. I am given the distance to the centre of the galaxy which is ##d##, I'm assuming that this is the radius of the orbit. I'm confused what this has to do with the period of orbit. Also, don't I need the radius of the black hole to take the ratio of the radius of the black hole to the radius of orbit in order to find the angular diameter?
 
Kynsuo said:
I am given the distance to the centre of the galaxy which is d, I'm assuming that this is the radius of the orbit.
No. d is the distance that the star & black hole system is from you, not the radius of the orbit of the star around the black hole.
Kynsuo said:
I'm confused what this has to do with the period of orbit.
The distance d has nothing to do with the period of the orbit.
Kynsuo said:
Also, don't I need the radius of the black hole to take the ratio of the radius of the black hole to the radius of orbit in order to find the angular diameter?
Think of it this way. You are observing, from a distance "d", a star orbiting a black hole. How big the orbit appears to you -- its angular diameter -- depends upon the size of the orbit (the diameter of the orbit) and how far away it is (the distance "d"). The first step is to calculate, using the given information, the size of the orbit. Only then can you worry about the angular diameter.
 
Thanks! This is what I was missing. Using the ##T##, ##G## and ##M##, I can find and expression for ##R##, the radius of orbit. Then once I have the orbit I can find the angular diameter. Thanks.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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