Calculating Angular Momentum for a Moving Object with a Given Force

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SUMMARY

The discussion focuses on calculating the angular momentum of a 0.25 kg object subjected to a force of 4.0j N. The position vector is given as r=(2.0i-2.0k) m, and the velocity vector is v=(-5.0i+5.0k) m/s. The participants computed the moment of inertia (I) as 2 kg·m² and the angular velocity (ω) as 2.5 rad/s. The key takeaway is that angular momentum (L) can be determined using the cross product of the position vector and the momentum vector (r x mv).

PREREQUISITES
  • Understanding of angular momentum and its formula (L = r x mv)
  • Knowledge of vector operations, specifically cross products
  • Familiarity with moment of inertia calculations (I = MR²)
  • Basic physics concepts including force, mass, and velocity
NEXT STEPS
  • Study the properties and applications of the cross product in physics
  • Learn about calculating angular momentum in different coordinate systems
  • Explore the implications of angular momentum conservation in closed systems
  • Review examples of moment of inertia for various shapes and configurations
USEFUL FOR

Students in physics, particularly those studying mechanics, as well as educators and anyone interested in understanding angular momentum calculations and vector operations.

Duderonimous
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Homework Statement


At one instant, force F=4.0j N acts on a 0.25 kg object that has a position vector r=(2.0i-2.0k) m and velocity vector v=(-5.0i+5.0k) m/s. About the origin and in unit-vector notation, what are (a) the objects angular momentum.


Homework Equations



L=I"omega", I=MR2, omega=v/r

The Attempt at a Solution


Computed resulant vectors r and v and got 2rad2 m and 5rad2 m/s respectively.

Computed I, M=0.25kg and R=2rad2m. Got 2kgm2.

Computed omega=v/r, v=5rad2 m/s and r= 2rad2 m. Got 2.5rad/s.

L did not come out looking so good.

Please help.

Thanks
 
Last edited:
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Hey there, Duderonimous! :wink:
Duderonimous said:
Computed resulant vectors of r and v and got 2rad2 m and 5rad2 m/s respectively.

I don't understand what this means. :confused:
Computed I, M=0.25kg and R=2rad2m. Got 2kgm2.

Computed omega=v/r, v=5rad2 m/s and r= 2rad2 m. Got 2.5rad/s.

Angular momentum (often called moment of momentum) is just r x mv, displacement "cross" momentum …

all you have to do is to "cross" the two vectors. :smile:
 
tiny-tim said:
Hey there, Duderonimous! :wink:


I don't understand what this means. :confused:

QUOTE]

I ment to say that I computed the magnitude of the resultant vectors. Which I got using the sqrt of the sum of the squares of the x and z components of both r and v.

Cross product eh...

Thanks.
 

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