Calculating Angular Speed of Venus

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Homework Help Overview

The discussion revolves around calculating the angular speed of Venus, specifically focusing on a point at the equator and another at a latitude of 11 degrees south. The original poster presents a question regarding the formulas to use, particularly mentioning the rotation period of Venus, which is 243 days.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the use of formulas related to angular speed and question the relevance of the rotation period. There is a suggestion to clarify whether the question pertains to orbital or rotational speed. Some participants explore the implications of latitude on angular speed and tangential speed.

Discussion Status

Some participants have made progress in calculating the angular speed for the equator, while others are still seeking clarification on how to approach the calculation for the latitude of 11 degrees south. There is a recognition that angular speed remains constant across latitudes, despite changes in tangential speed.

Contextual Notes

Participants note the importance of distinguishing between angular speed and tangential speed, as well as the need for trigonometric considerations when calculating the radius of the circle at different latitudes.

Cate
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Hi all, my homework question is this:

1. What is the angular speed in rad/s of a point on the equator of venus? (Rotation period: 243 days)

2. What is the angular speed in rad/s of a point on the surface of venus at latitude 11 degress south?

I know this isn't that difficult but I can't get the answer I thought maybe you use the formula

V= square root (GM/r) and then use the formula v= rw to solve for angular speed but then that doesn't take into account the 243 days...


AS for the second question I have no idea

If anyone could point me into the right direction it would be appreciated...
 
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Cate said:
Hi all, my homework question is this:

1. What is the angular speed in rad/s of a point on the equator of venus? (Rotation period: 243 days)

2. What is the angular speed in rad/s of a point on the surface of venus at latitude 11 degress south?

I know this isn't that difficult but I can't get the answer I thought maybe you use the formula

V= square root (GM/r) and then use the formula v= rw to solve for angular speed but then that doesn't take into account the 243 days...AS for the second question I have no idea

If anyone could point me into the right direction it would be appreciated...

Think about what you are asked.

Is the question about the orbital period around the sun?

Or the rotational period about its axis?
 
o.k i solved 1. 2(pi)/ (20995200) # of seconds in 243 days.

I'm still stuck on ow to go about solving for 2.
 
could someone please explain to me how to actor 11 degrees n question #2?

Thanks
 
Cate said:
could someone please explain to me how to actor 11 degrees n question #2?

Thanks

What difference in angular rate will a point at 11 degrees rotate at?
 
A particle at some point on the equator moves around in a great circle whose circumference is equal to the circumference of the planet (by definition). So you know how much *distance* the particle moves through, and you know how much *time* it takes to do so. Sooo...

A particle at 11 degrees latitude moves around in a circle that is smaller than the equator. To figure out how to calculate this circle's radius, I would draw a diagram...there is some trigonometry involved.
 
cepheid said:
A particle at some point on the equator moves around in a great circle whose circumference is equal to the circumference of the planet (by definition). So you know how much *distance* the particle moves through, and you know how much *time* it takes to do so. Sooo...

A particle at 11 degrees latitude moves around in a circle that is smaller than the equator. To figure out how to calculate this circle's radius, I would draw a diagram...there is some trigonometry involved.

While the Tangential speed will be affected by latitude, the angular velocity will not because the distance to the axis shrinks in direct proportion to its speed with increasing latitude. All points along a meridian travel at the same Angular speed. The answer is in radians/sec the same as for part 1.
 
oh whoops...I didn't read the question properly. Didn't know we were looking for *angular* speed. Good catch.
 
cepheid said:
oh whoops...I didn't read the question properly. Didn't know we were looking for *angular* speed. Good catch.

No problem. Hated to have to give away the answer, but didn't want to confuse.

Cheers.
 

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