Calculating Area of Shaded Region in Picture

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SUMMARY

The area of the shaded region can be calculated using geometric principles without the need for calculus. By approximating the boundaries as circular arcs, the area can be determined using the formula for the area of a sector. Specifically, if the upper boundary is a circle with radius r, deflection wpk, and chord length 2a, the area of the sector is given by 2arccos((r-wpk)/r) multiplied by r². For the outer arc, the radius becomes r+t, and the same formula applies, allowing for the subtraction of the two areas to find the desired shaded region.

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  • Understanding of basic geometry, particularly circular sectors
  • Familiarity with the Pythagorean theorem
  • Knowledge of trigonometric functions, specifically arccosine
  • Ability to manipulate algebraic expressions
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  • Study the properties of circular sectors and their areas
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  • Explore trigonometric functions and their inverses, focusing on arccos
  • Practice solving geometric problems involving arcs and sectors
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ruzfactor
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Hi

How can I calculate the area of the shaded region in picture attached? Please suggest.
 

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The way you have shown it, the boundaries are rather complicated, and not specifically determined, functions. Do you mean to approximate them by circles? If the upper boundary, for example, is a circle with radius r, deflection wpk, and chord 2a, then we can look at the right triangle, with one vertex at the center of the circle, having one leg of length r- wpk, one leg of length a, and hypotenuse of length r. By the Pythagorean theorem, we have a^2= r^2- (r- w_{pk})^2= 2rw_{pk}- w_{pk}^2. More importantly, the angle at the center of the circle is arccos((r-w_{pk})/r) so we have a sector of a circle of radius r covering an angle of 2arccos((r- w_{pk})/r). The has area 2arccos((r- w_{pk}/r) r^2.

For the outer arc, you have the same thing except that instead of "r", the radius is "r+t". Use the same formula, replacing r by r+ t, and subtract the two areas to find the area you want. There is no Calculus required here.
 

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