Calculating Average Size of Target Square in Unit Square with Variable p^2

Click For Summary
SUMMARY

The discussion focuses on calculating the average size of a target square with dimensions LXL = p^2, where p^2 is less than 1, positioned within a unit square. The key point is to determine the area of intersection between the target square and the unit square, denoted as A = T ∩ U. When the center of the target square is within the boundaries defined by p ≤ x ≤ 1-p and p ≤ y ≤ 1-p, the area A equals p^2. The discussion emphasizes the need to analyze scenarios where the target square's center approaches the unit square's edges, affecting the area calculation.

PREREQUISITES
  • Understanding of geometric concepts related to squares and areas.
  • Familiarity with coordinate systems in two-dimensional space.
  • Basic knowledge of intersection areas in geometry.
  • Ability to manipulate inequalities and boundaries in mathematical contexts.
NEXT STEPS
  • Explore geometric probability to understand average area calculations.
  • Research methods for calculating intersection areas of geometric shapes.
  • Learn about boundary effects on area calculations in geometry.
  • Investigate the implications of varying p values on the average size of the target square.
USEFUL FOR

Mathematicians, geometry enthusiasts, and students studying geometric probability and area calculations will benefit from this discussion.

purplebird
Messages
14
Reaction score
0
Given a unit square and a 'target' square of size LXL = p^2 < 1 in the unit square. The center of target square in equally likely to be anywhere in the unit square. What is the average size of the target square as a function of p^2.

This is the problem and I have included a jpeg illustration of the problem. Any help would be greatly appreciated.
 

Attachments

  • pic.jpg
    pic.jpg
    6 KB · Views: 432
Physics news on Phys.org
purplebird said:
Given a unit square and a 'target' square of size LXL = p^2 < 1 in the unit square. ... What is the average size of the target square as a function of p^2.

The size of the "target square" is p^2 by the statement of the problem. :smile:

Do you mean the intersection of the target square T with the unit square [itex]U=[0,1]\times[0,1]\subset \mathbb{R}^2[/itex]? In this case I suggest you first try and find out what the area of [itex]A = T\cap U[/itex] is as a function of the center of the target square. Denote this center by (x,y).

Then for [itex]p \leq x\leq 1-p \wedge p \leq y\leq 1-p[/itex] you have A=p^2. Figure out the area A if the center of the target space is too close to the boundary of the unit square for the former to completely fit into the latter.
 
Last edited:

Similar threads

  • · Replies 3 ·
Replies
3
Views
871
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 20 ·
Replies
20
Views
4K
  • · Replies 11 ·
Replies
11
Views
4K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 7 ·
Replies
7
Views
8K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 12 ·
Replies
12
Views
4K