Calculating Ball Height from Horizontal Force: Newton's Second Law Explained

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ippo90
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Exams tomorow! please help

Homework Statement



A billiard ball is hit with a horizontal force F. The force hits the ball with the height h over the ball's center. the initial velocity is v0 and the the velocity afterward is (9/7)v0. Show that the height h is (4/5)R, where R is the radii of the ball.

Homework Equations



Newtons second law: Fdt=mdv

momentum: t=r x F=Iw

The Attempt at a Solution


I don't really understand this. please help. Thank you very much
 
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hi ippo90! :smile:

initially, the ball will slide (at velocity v0) while spinning, but after a short time, friction will reduce the spin, and the ball will start rolling (at velocity (9/7)v0) :wink:
 


Thank you for the reply. The problem is I don't know where to start. Can you help me?
 


just ignore my last post. I thought about what you said in you post, and it came out=) Thank you for your kind help.

one thing I not sure of is that when I integrated the torque i got something like

hFt=Iw

where h is height, t is time and w is the angul. velocity. here I chose the center as the point of momentum. but afterward I have to use that the angular momentum (L) is conserved. but this means that I have to choose the contact point as the poiint of momentum. why can I do this (why not)?
 


ippo90 said:
just ignore my last post. I thought about what you said in you post, and it came out=) Thank you for your kind help.

one thing I not sure of is that when I integrated the torque i got something like

hFt=Iw

where h is height, t is time and w is the angul. velocity. here I chose the center as the point of momentum. but afterward I have to use that the angular momentum (L) is conserved. but this means that I have to choose the contact point as the poiint of momentum. why can I do this (why not)?

It would be nice to see the problem worked out in detail.