Calculating Barium Phosphate Formation: 10th Grade Chemistry Example

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SUMMARY

The discussion centers on calculating the formation of barium phosphate (Ba3(PO4)2) from the reaction of 127.2 grams of potassium phosphate (K3PO4) with 75.6 grams of barium chloride (BaCl2). The calculated yield of barium phosphate is 72.82 grams, although variations in the answer are attributed to differences in molar masses used in the calculations. Participants confirm the method used for the calculation and emphasize the importance of accurate molar mass values in stoichiometric calculations.

PREREQUISITES
  • Understanding of stoichiometry in chemical reactions
  • Knowledge of molar mass calculations
  • Familiarity with the chemical formulas of potassium phosphate and barium chloride
  • Basic principles of chemical reaction yield
NEXT STEPS
  • Study stoichiometric calculations in detail
  • Learn how to accurately calculate molar masses of compounds
  • Explore the concept of limiting reactants in chemical reactions
  • Investigate the practical applications of barium phosphate in chemistry
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High school chemistry students, educators teaching stoichiometry, and anyone interested in chemical reaction calculations.

ProblemSets
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How many grams of barium phosphate will form when 127.2 grams of potassium phosphate reacts with 75.6 grams of barium chloride?


I get 72.82 grams of Ba3(PO4)2?


Is this correct?
 
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Show your working.
 
close enough. my answer probably varies because of a slight difference in molar masses.
 

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