Calculating Bathysphere Mass for Constant Descent at 1.10 m/s

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SUMMARY

The discussion focuses on calculating the mass a bathysphere must take on to maintain a constant descent speed of 1.10 m/s while overcoming a resistive force of 1102 N. Given the bathysphere's radius of 1.52 m and its initial mass of 1.20 x 104 kg, the equation of motion reveals that the gravitational force, buoyant force, and resistive force must balance. The density of seawater is specified as 1.03 x 103 kg/m3, which is essential for determining the buoyant force acting on the bathysphere.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Knowledge of buoyancy principles
  • Familiarity with the concept of resistive forces in fluid dynamics
  • Basic skills in algebra for solving equations
NEXT STEPS
  • Calculate the volume of the bathysphere using the formula for the volume of a sphere: V = (4/3)πR3
  • Learn about the relationship between mass, density, and volume in fluid mechanics
  • Explore the implications of constant velocity in dynamic systems
  • Investigate the effects of varying resistive forces on submerged objects
USEFUL FOR

This discussion is beneficial for marine engineers, physicists, and students studying fluid dynamics or underwater vehicle design, particularly those interested in the mechanics of deep-sea exploration vehicles.

jenha14
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A bathysphere used for deep-sea exploration has a radius of 1.52 m and a mass of 1.20 x 104 kg. To dive, this submarine takes on mass in the form of sea water. Determine the amount of mass that the submarine must take on if it is to descend at a constant speed of 1.10 m/s, when the resistive force on it is 1102 N in the upward direction. The density of seawater is 1.03 x 103 kg/m3.

ATTEMPT AT SOLUTION
When the bathysphere descends at constant velocity the sum on the force acting on it equals zero:
m · a = Σ F = 0
<=>
F_gravity - F_buoyancy - F_resistive = 0
<=>
m·g - ρ_water·V_sphere·g - F_resistive = 0
<=>
m·g - ρ_water·(4/3)·π·(R_sphere)³·g - F_resistive = 0
 
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