Calculate Power of Cable Force Moving Elevator Cab: 3.0x103 kg, 191 m, 23 s

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SUMMARY

The discussion centers on calculating the average power exerted by the cable force on an elevator cab with a mass of 3.0 x 103 kg, moving 191 m in 23 seconds. The correct approach involves using the formula for power, which is the product of force and velocity. The tension in the cable, equal to the gravitational force (mg), is multiplied by the velocity calculated as 191 m / 23 s. The final result must be converted from watts to kilowatts (kW) for proper reporting.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with the concepts of work and power in physics
  • Basic knowledge of gravitational force calculations
  • Ability to perform unit conversions, specifically from watts to kilowatts
NEXT STEPS
  • Review the principles of Newton's second law and how it applies to tension in cables
  • Study the relationship between work, power, and energy in mechanical systems
  • Learn about the dot product in physics and its application in calculating power
  • Practice converting units of power, focusing on the transition from watts to kilowatts
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Students and professionals in physics, engineering, and mechanics who are involved in elevator design, cable systems, or energy calculations in moving systems.

themanofosu
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Question: The loaded cab of an elevator has a mass of 3.0 103 kg and moves 191 m up the shaft in 23 s at constant speed. At what average rate does the force from the cable do work on the cab? answer is in kW

hint provided : Power is the rate at which work is done. The power of a force is the dot product of the force and the velocity. If the cab moves at constant speed, how does the cable's force compare with the gravitational force on the cab?

So I am guessing tension which equals mg is our force, and so that force times velocity, which is 191/23 m/s is our power. what did i do wrong? how do you solve this properly? thank you! :D
 
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Welcome to PF!

Hi themanofosu ! Welcome to PF! :smile:

(try using the X2 tag just above the Reply box :wink:)

You haven't actually shown us your final figures, but your method looks correct …

did you remember to convert from W to kW ? :smile:​
 

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