Calculating Braking Force for a Moving Car

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SUMMARY

The discussion focuses on calculating the braking force required to stop a car weighing 1,200 kg traveling at 22.5 m/s over a distance of 112 m, assuming uniform deceleration. The relevant equations include Fnet = Fapp - FR, Fnet = ma, and Fg = mg. The user suggests using the deceleration formula a = -((v2 - v1)²) / (2 * s) to find the necessary values. The main challenge identified is determining the applied force and resistive force in the braking scenario.

PREREQUISITES
  • Understanding of Newton's Second Law (F = ma)
  • Familiarity with kinematic equations for uniformly accelerated motion
  • Basic knowledge of forces, including applied and resistive forces
  • Ability to perform calculations involving mass, velocity, and distance
NEXT STEPS
  • Calculate deceleration using the formula a = -((v2 - v1)²) / (2 * s)
  • Determine the net force using Fnet = ma after finding deceleration
  • Identify the applied force (Fapp) and resistive force (FR) in the braking context
  • Explore real-world applications of braking force calculations in automotive engineering
USEFUL FOR

Students studying physics, automotive engineers, and anyone interested in understanding the dynamics of vehicle braking systems.

Jyote25
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Homework Statement



A 1.20x103 kg car is traveling at a speed of 22.5 m/s when the brakes are applied. If the car comes to a stop in 112m, what is the braking force?(Assume Uniform deceleration)

Homework Equations



Fnet=Fapp-FR

Fnet=ma

Fg=mg



The Attempt at a Solution












Thank you for your help!
 
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Consider the deceleration to be [tex]a=-\frac{((v_{2}-v_{1})^{2})}{2 \cdot s}[/tex].

Insert [tex]v_{2}=0~m/s[/tex], [tex]v_{1}=22.5~m/s[/tex], [tex]s=112~m[/tex].
 
Thanks for your help Lunar Lander, the formula definitely helps :smile: but what I'm having the most trouble with(I should have included this in the question) is knowing what is the Force Applied, Resistive force, etc...any ideas? Thanks again.
 

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