Breaking Distance of a Car Traveling on an Inclined Plane

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SUMMARY

The discussion focuses on calculating the braking distance of a car traveling at 35.0 m/s down a 10.0-degree incline. The total force acting on the car is expressed as F = ma - mgsin(10), where 'a' represents the original acceleration. Participants highlight the need for additional information, such as the car's mass and normal acceleration, to accurately determine braking distance. The conversation emphasizes the distinction between static and kinetic friction and its impact on braking force.

PREREQUISITES
  • Understanding of Newton's Second Law (F=ma)
  • Basic knowledge of trigonometry (sine function)
  • Familiarity with concepts of static and kinetic friction
  • Ability to manipulate kinematic equations (v=u + 2as)
NEXT STEPS
  • Research the effects of incline angles on braking distance calculations
  • Study the differences between static and kinetic friction in automotive contexts
  • Explore advanced models of braking force that account for incline effects
  • Learn how to derive acceleration from forces acting on an object on an incline
USEFUL FOR

Students studying physics, automotive engineers, and anyone interested in understanding the dynamics of vehicles on inclined planes.

Emma Hughes
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Homework Statement


Calculate the braking distance for a car traveling at a speed of 35.0m/s down a hill at an angle of 10.0 degrees relative to the horizontal.

Homework Equations


F=ma
v=u + 2as[/B]

The Attempt at a Solution


The teacher briefly explained this in class saying that the total force acting on the car when the braking force is applied (with direction of braking force as positive) is: ma - mgsin10, with a being the original acceleration of the car.

Although I don't understand how to get the original acceleration of the car or why it is used to get the braking force of the car.
 
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Emma Hughes said:

Homework Statement


Calculate the braking distance for a car traveling at a speed of 35.0m/s down a hill at an angle of 10.0 degrees relative to the horizontal.

Homework Equations


F=ma
v=u + 2as[/B]

The Attempt at a Solution


The teacher briefly explained this in class saying that the total force acting on the car when the braking force is applied (with direction of braking force as positive) is: ma - mgsin10, with a being the original acceleration of the car.

Although I don't understand how to get the original acceleration of the car or why it is used to get the braking force of the car.

I think that ##a## here is the deceleration of the car by braking on a horizontal road. Hence ##ma## is the braking force of the car.

On an incline you have gravity accelerating you, which is the second term in the equation.

Note that in this model it is assumed that the braking force of the car itself isn't affected by the angle. You might like to think about this and why in a more sophisticated model this may not be the case.
 
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PeroK said:
I think that ##a## here is the deceleration of the car by braking on a horizontal road. Hence ##ma## is the braking force of the car.

On an incline you have gravity accelerating you, which is the second term in the equation.

Note that in this model it is assumed that the braking force of the car itself isn't affected by the angle. You might like to think about this and why in a more sophisticated model this may not be the case.
Whether the angle affect the braking force would depend on if the car is skidding (kinetic friction between tire and road) or the tires remain rolling (static friction between road and tire).
Reading the problem statement - the mass is not given, nor the "normal" acceleration.

So more information is needed to solve this.
 

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