The discussion focuses on calculating the buoyancy force and tension in the cable for a 6-meter spherical undersea research chamber with a mass of 75,200 kg. The buoyant force is calculated using the formula F_B = (4/3)πr^3ρ_water g, yielding a result of approximately 8.87 x 106 N. Participants emphasize the importance of using the correct radius (3 m) and applying Newton's second law to determine the tension in the cable. Miscalculations stem from incorrect assumptions about volume and displacement.
PREREQUISITESStudents and professionals in physics, marine engineering, and underwater research who are involved in buoyancy calculations and tension analysis in submerged structures.
What in am doing wrong? I assumed it's just the volume of the tank and then you find the weight of the water displaced. It's not working. I made sure that the diameter was changed into a radius for the volume of the sphere. Also as a sanity note, if you have a tank that sinks when it's empty it should still sink if it's full of air right?
Yeah which is why I hate it when I get these problems wrong.:) I know that has to be the answer. I can't figure out why I am not getting the right number. Here is what I am getting. 1108353.888 Newtons.
<br /> <br /> Dex why are you writing hieroglyphs for very simple formulas <img src="https://www.physicsforums.com/styles/physicsforums/xenforo/smilies/oldschool/bugeye.gif" class="smilie" loading="lazy" alt=":bugeye:" title="Bug Eye :bugeye:" data-shortname=":bugeye:" /> .<br /> <br /> Adam, F_B = \frac{4}{3}\pi r^3\rho_{w}g = F_B = \frac{4}{3}\pi (6m)^3(1000kg/m^3)(9.8m/s^2) = 8.87 * 10^6 N. <br /> Right?dextercioby said:
Yeah. Your equation is right. Though don't you need to divide the diamter by two to get the radius? I checked neither of those two possible solutions are correct.
