Calculating Buoyancy in Oil/Water: Solving for Height of Cylinder

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SUMMARY

The discussion focuses on calculating the height of a solid cylinder submerged in a mixture of water and oil. The cylinder has a radius of 0.150 m, a height of 0.120 m, and a mass of 6.90 kg. The buoyancy equation used is (p)water(g)(V)water + (p)oil(g)(V)oil = mg, where the density of oil is 725 kg/m³. Participants discuss how to derive the volume of oil and the height submerged in oil using the total buoyant force and the dimensions of the cylinder.

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1. A solid cylinder (radius = 0.150 m, height = 0.120 m) has a mass of 6.90 kg. This cylinder is floating in water. Then oil ( = 725 kg/m3) is poured on top of the water until the situation shown in the drawing results. How much of the height of the cylinder is in the oil?



2. (p)water(g)(V)water + (p) oil(g)(V) oil= mg
(V)water+ (V)oil= (V)cylinder
(h)oil= (V)oil/area of cylinder



3. using what i was given, i was able to calculate the area and volume of the cyclinder, which was easy enough. i know that once i use the first equation to get the volume of the oil I am supposed to subtract it from the volume of the cylinder. unfortunately I am not sure how to figure out the volume of the oil using the equation we were given (the first one i listed)
 
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I can't see any drawing.
 
Shooting star said:
I can't see any drawing.

http://smg.photobucket.com/albums/v456/andpull/?action=view&current=cylinder.gif
 
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Total buoyant force upward = weight of water displaced + weight of oil displaced. Is this enough for you to proceed?

Take h as the height of the cylinder in oil. Then H-h is in water, where H is ht of cylinder. Try it out.
 

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