Calculating Car Accident Speed: 100ft skid marks, 0.75g deceleration

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SUMMARY

The discussion focuses on calculating the minimum speed of a car at the moment it applied brakes, given a skid mark length of 100 feet and a maximum deceleration of 0.75g on dry pavement. The relevant kinematic equation used is vf² = v0² + 2as, where vf is the final velocity (0), v0 is the initial velocity, a is the acceleration (negative due to deceleration), and s is the displacement (100 feet). The calculation yields an initial velocity of 21.2 m/s, which converts to approximately 47.4 mph, confirming the correctness of the approach taken by the participant.

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Homework Statement



Investigating the scene of a car accident you measure the skid marks of one of the cars to be 100.0ft long. Assuming that the maximum deceleration on dry pavement is 0.75g, what was the minimum speed of the car(in mph) when it slammed on the brakes?

Homework Equations



x=x0 + v0t +1/2at^2
v=v0 + at

The Attempt at a Solution



I know I need to solve for t, but I can't seem to wrap my ahead around setting up the equations for these types of problems. A helpful nudge would be appreciated.
 
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You don't need to solve for time, you are asked to solve initial velocity. You are given 3 values, displacement, acceleration, and final velocity.
 
I was under the impression that most of these problems begin with solving for time. I'm really in the dark on this stuff. My instructor leaves much to be desired.
 
Have you been taught all of the basic kinematic equations?

If so, look at each of them. You'll find that each one has a different variable missing.

Knowing this all you have to do is look for the equation with all the variables you're given and the variable you need and then use that.
 
This is what I did...let me know if I'm on the right track.

I used vf2 + v02 = 2as.

so v02 = 2(7.35m/s2)(30.48m)
v0 = 21.2m/s

I think that's right, but I'm not sure. Then of course I have to convert to mph. Am I close?
 
Yes, that is correct.
 

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