Calculating Center of Mass of a Car: Step-by-Step Guide

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Homework Help Overview

The original poster attempts to calculate the center of mass of a car using weight measurements from a scale as the car is driven over it. The problem involves understanding the relationship between the weights on the front and rear wheels and the distance between them.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the equations derived from the weight measurements and the distance between the wheels. There is an exploration of different mathematical relationships, including a comparison to a see-saw model. Questions arise regarding the values used in the equations and the reasoning behind them.

Discussion Status

The discussion is ongoing, with participants clarifying their understanding of the equations involved. Some guidance has been offered regarding the setup of the equations, but there is no explicit consensus on the correct approach yet.

Contextual Notes

Participants mention the challenge of understanding the problem due to exam stress, which may affect their clarity in reasoning and communication.

kaylanp01
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Homework Statement


To determine the location of the center of mass of a car, the car is driven over a scale. When the front wheels are over the scale, the weight recorded by the scale is 5.05 x 103 N. When the rear wheels are over the scale, the scale reads 6.20 x 103 N. The distance between the front and rear wheels is 3.58 m. How far behind the front wheels is the center of mass located?


Homework Equations


Ahh I did it using that math that we used in lower level high school. haha. Thought I might get lucky.

I missed these classes in physics, so I'm trying to figure it out and have no idea where to start.


The Attempt at a Solution


I did:
x + y = 3.58
5050x + 6200y = 112500 (because the weight of the car is equal to the sum of the weight measured on the front wheel and the weight measured on the rear wheel).
Solved for x, subbed it in, got the wroong answer. aha.
 
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Maybe if you had thought of the see-saw?

Won't it be more like 5*x = 6.2(3.58 - x) ?
 
LowlyPion said:
Maybe if you had thought of the see-saw?

Won't it be more like 5*x = 6.2(3.58 - x) ?

Sorry...I'm not following. Where did the 5 come from?
 
OK. 5.05 if you prefer.
 
LowlyPion said:
OK. 5.05 if you prefer.

oooh. hahah sorry. its exam week, I'm feeling a bit slow. so your formulas are actually x + y = 3.58 and then 5x = 6y. I understand, thank you :).
 
kaylanp01 said:
oooh. hahah sorry. its exam week, I'm feeling a bit slow. so your formulas are actually x + y = 3.58 and then 5x = 6y. I understand, thank you :).

Basically, yes.

Where did your 6 come from then?

JK.

Cheers.
 
LowlyPion said:
Basically, yes.

Where did your 6 come from then?

JK.

Cheers.

hahah now now, be nice.
 

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