Calculating Center of Mass of a Hollow Nose Cone

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To calculate the center of mass of a hollow nose cone, the formula is given as π&radic(h2+R2)hR/M, where R is the base radius, h is the height, and M is the mass. An alternative method involves suspending the cone from different points and marking the vertical lines created; the intersection of these lines indicates the center of mass. This approach can help in practical applications, such as determining fin placement for a rocket project. The discussion emphasizes the importance of accurately finding the center of mass for stability in rocket design. Understanding these methods is crucial for successful rocket construction.
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I am working on a rocket and need to find the center of mass of a hollow nose cone. Any help would be appreciated.
 
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If the "nose cone" is a cone with base radius R and height h, with mass M, then the center of mass is on the axis at distance π&radic(h2+R2)hR/M.
 
Here's an alternate way, if its any easier for you. Suspend the hollow nose cone from a chosen point (by attaching a string to any point of the cone) and there will be a vertical line (90 degress relative to the Earth). Remember where this vertical line is. Then choose a different suspension point. The center of mass is where these two vertical lines intercect. Look at the pic if it helps. And make sure to do this with the same "side" of the cone.
 

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thanks for the help. I am working on a big rocket project and needed to find the center of mass for each part so we can figure out where we need to locate the fins.
 
Thread 'Correct statement about size of wire to produce larger extension'

Thread 'Correct statement about size of wire to produce larger extension'

The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...
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