Calculating Centripetal Acceleration of Space Telescope in Orbit

  • Thread starter Thread starter mohabitar
  • Start date Start date
  • Tags Tags
    Gravitational
Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
1 replies · 2K views
mohabitar
Messages
140
Reaction score
0
I've done a bunch of these before, but don't know why I'm not getting the right answer this time around:

A space telescope of mass m[t]=10,000 kg is in a stable circular orbit above the Earth at an altitude h=3630 km. The radius and mass of the Earth are R[e]=6370 and M[e]=6x10^24 kg. Newtons gravitational constant is 6.672x10^-11.

What is the acceleration of the space telescope as it orbits the earth?

_____________

So this is simple enough-we're looking for the centripetal acceleration. So m[t]*Ac=GM[e]m[t]/R^2[earth center to satellite]. The m[t]'s cancel out, so we have centripetal acceleration =GM[e]/R^2, and I'm getting a really large number, even though the answer is supposed to be 4.0 m/s^2. What do you see I'm doing wrong?
 
on Phys.org