Calculating Centripetal Force: 40.0kg Child on 9.0m Ferris Wheel

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SUMMARY

The discussion centers on calculating the centripetal force exerted by a Ferris wheel seat on a 40.0 kg child positioned halfway between the top and bottom of the wheel. The Ferris wheel has a radius of 9.0 m and rotates at a rate of four times per minute. The calculated force exerted by the seat on the child is 397 N, which is 5 N greater than the child's weight. This additional force accounts for the centripetal force necessary to maintain the child's circular motion.

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A 40.0 kg child on a Ferris wheel rotates four times each minute and the wheel has a radius of 9.0 m.

What force does the seat exert on the child when the child is halfway between the top and bottom?

The answer is 397 N which is 5 N more than the weight of the child, but I have not idea how they got that, anyone have any ideas?
 
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HINT: The seat also supplies the centripetal force to keep the child moving in a circular path.
 

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