Calculating Charge Entering an Element: Q=6.667 C

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Homework Help Overview

The problem involves calculating the charge entering an electrical element over a specified time interval, given a piecewise current function. The subject area pertains to electrical circuits and charge calculation.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the use of integration to calculate charge based on current, with some questioning the appropriateness of the integral method for a constant current scenario. There are attempts to clarify the relationship between current and charge, particularly in the context of piecewise functions.

Discussion Status

The discussion has seen participants exploring different methods to approach the problem, with some expressing uncertainty about their understanding. One participant has indicated they found a solution independently after initial confusion, suggesting some productive direction has emerged.

Contextual Notes

There is mention of the participant's self-identified status as a newbie, which may imply a learning curve in understanding the concepts involved. The problem's piecewise nature introduces complexity that some participants are grappling with.

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Homework Statement



The current flowing through an element is i = 2 A for 0<t<1 and i = 2t^2 A for t>1
Calculate the charge entering the element from t=0s to t=2s.
Answer: 6.667 C.


Homework Equations


I used Q=t1∫t2 i dt



The Attempt at a Solution


I tried to solve using integral method. but how to proceed here as for 0<t<1 i is constant and i am stuck. Are there any other methods.
 
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I think this is a very basic problem but still I cannot do it because i am a newbie and may be to need work harder. Sorry for consuming your time.
 


If the current is constant over a given time interval, how much charge is accumulated? Remember, 1 ampere = 1 coulomb / second.

Why did you chose the integral method to solve this problem if you cannot integrate a constant function?
 


SteamKing said:
If the current is constant over a given time interval, how much charge is accumulated? Remember, 1 ampere = 1 coulomb / second.

Why did you chose the integral method to solve this problem if you cannot integrate a constant function?
Thank you for pointing out. I made this post in hurry without thinking. And now i got the answer myself.

for 0s to 1s i = 2A so q = 2C

for 1s to 2 s i calculated by integrating i wrt dt between 1s to 2s

and added two values and the answer is correct.
 

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