Calculating coulombs law in a capacitor?

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SUMMARY

The discussion focuses on calculating the electric field in a capacitor rather than applying Coulomb's law directly. The capacitor in question has a plate area of 5 inches and a separation of 10 mm, with a total charge (Q) of 0.002 Coulombs. Participants clarify that Coulomb's law, which describes the force between two point charges, is not applicable for capacitors. Instead, the correct approach involves calculating the electric field (E) and using the formula F = qE to determine the force on a charge within the field.

PREREQUISITES
  • Understanding of electric fields and forces
  • Familiarity with capacitor design and specifications
  • Knowledge of Coulomb's law and its limitations
  • Basic algebra for manipulating equations
NEXT STEPS
  • Learn how to calculate the electric field in a parallel plate capacitor
  • Study the relationship between charge, electric field, and force
  • Explore the concept of charge distribution in capacitors
  • Review the derivation of the capacitance formula for parallel plate capacitors
USEFUL FOR

Students in physics or electrical engineering, educators teaching electromagnetism, and anyone seeking to understand capacitor behavior and electric field calculations.

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Homework Statement



Each capacitor has a plate area of 5 inches, with a distance between the plates of 10mm. The capacitor has a total Q of .002 Coulombs.



Homework Equations



Coulombs law F=Ke X q1q2/r squared

The Attempt at a Solution



I do not know how to calculate coulombs law for a capacitor since coulombs law only describes the force between 2 points. Do I need to calculate the charge distribution first? How do I do that?
 
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Yeah, you can't use coulomb's law. You should find the electric field then use the fact that F=qE.
 

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