Calculating Current in a Coil with Given Magnetic Field and Parameters

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To calculate the current in a 50-turn coil with a radius of 15 cm and a magnetic field of 0.60 mT, the relevant formula for the magnetic field at the center of a circular loop is B = (magnetic permeability * I) / (2r). Since the coil has 50 turns, the total magnetic field can be expressed as B = (magnetic permeability * N * I) / (2r), where N is the number of turns. By rearranging the equation and substituting the known values, the current is found to be approximately 2.9 A. This confirms that the magnetic field strength for multiple turns is indeed additive, leading to a straightforward calculation. The discussion effectively resolves the confusion regarding the application of the formula for a multi-turn coil.
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"The magnetic field at the center of a 50-turn coil of radius 15 cm is 0.60mT. find the current in the coil."
N=50, r = .15m, B = 6.0 * 10^-4 T, magnetic permeability = 4 * pi * 10^-7.

B = (mag.per. * N * I)/ L
However, I don't have L, which is the length. I do have r, the radius, but it's not in the equation... How do i solve this?
 
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This is not a solenoid, just a ring of wire. A hoola hoop.
 
then what does "a 50-turn coil" mean?
my book gives me the equation for finding the magnetic field in the center of a circular loop: B = (mag. per. * I)/(2r). But then how do I factor the "50-turn coil" in? Is this simply superfluous information?
 
Think about it: You have the formula for the field at the center of a single circular loop of current-carrying wire, so what would you expect the field to be for 50 of them combined?
 
50 times the strength I suppose...

well, that does work out:
1/50 B = (mag.per. * I)/(2r)
and solving for I, I get: I = 2.9A, which is the right answer.

Thanks.
 
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