Calculating Density of Oxygen at STP

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To calculate the density of oxygen at standard temperature and pressure (STP), the ideal gas law (PV=nRT) is essential. The molar mass of O2 is 32 grams per mole, as it consists of two oxygen atoms, each weighing 16 grams. Using the molar volume of 22.4141 liters at STP, density can be determined by dividing the molar mass by the molar volume. The correct calculation involves using n=1 mole for the ideal gas law, leading to a density of approximately 1.40 g/L for oxygen. Accurate unit conversion and understanding of molecular mass are crucial for these calculations.
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Ok, I know I have to use the ideal gas law, but am not exactly sure how to apply that to finding the density.

PV=nRT (ideal gas law)

1atm (volume) = n(number of moles - can I just use 1 for ease?)(8.315 J(mol•K) (temperature)

Not quite sure where to go from here, any help would be appreciated just to get me in the right direction. Do I need the density of Oxygen at another temperature in order to do this?
 
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Tom,
density of an element at stp is its mass/volume.
Since-breathable- oxygen is 2 atoms at standard temp(293-298K) and pressure(1atm), you need to account for O2-- 16 grams per mole, i.e., n=2.
Do you have the "unit" volume?
nrt/p = V.
you can get its atomic mass from the periodic chart.
A decent (one bought from the college bookstore for $5.00) chart would also have the unit density on it as well.
Hope this is helpful.
 
SteveDB said:
Tom,
Since-breathable- oxygen is 2 atoms at standard temp(293-298K) and pressure(1atm), you need to account for O2-- 16 grams per mole, i.e., n=2.
Do you have the "unit" volume?
nrt/p = V.

Shortly after my post I realized that the atomic mass was the piece that I was missing, so to find n I did n=(mass)/(molecular mass), n=1gram/16, and after plugging that all in, I got a final density of 1.40 (which is basically much that of oxygen). Was I right to use n=1/16 or was it n=2? Thanks for the help.
 
The molar volume at stp is 22.4141L as I recall. This is easily calculated with the ideal gas law using 1 mole and stp, be sure to use correct units for your R. From there the density will be molar mass/molar volume.
 
I found this claculation by chance and I noticed a mistake. Molecular mass for O2 is 32, not 16 because the O2 molecule is formed by two O atoms which mass is 16 each.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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