Calculating Displacement with Negative Work

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Homework Help Overview

The discussion revolves around calculating displacement in the context of negative work applied to a car that is decelerating. The original poster presents a scenario involving a car moving at a constant velocity that slows down due to an opposing force, seeking to understand the implications of negative work on displacement.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the relationship between force, work, and displacement, particularly in scenarios involving negative work. Questions arise regarding the direction of displacement when opposing forces are applied, and whether the calculated displacement should be considered positive or negative.

Discussion Status

Some participants provide feedback on calculations, suggesting a need for re-evaluation. There is a recognition of the complexity of the concept, with analogies offered to aid understanding. Multiple interpretations of displacement direction are being discussed, indicating an ongoing exploration of the topic.

Contextual Notes

Participants note the challenge of reconciling the direction of force and displacement, particularly in the context of deceleration and negative work. There is mention of potential errors in calculations, which may affect the understanding of displacement in this scenario.

Red_CCF
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I'm trying to figure out how to find the displacement when negative work is applied. I made the question myself so it could not make any sense at all, I'm just trying to understand a concept on my own.

Homework Statement



A car (2000kg) is moving at constant velocity at 4m/s to the right. It slows down to 1m/s in a time of 3s when an external force is applied against the car to the left. What is the displacement of the negative work?

Homework Equations



a=change in velocity/time
F=ma
W=Fd
Ek=1/2mv^2

The Attempt at a Solution



Using the above formulas I get an acceleration of -1m/s^2 (or 1m/s^2 left). This must mean that the force that opposes the motion of the car is -2000N (or 2000N left). The initial kinetic energy of the car is 16000J and the final kinetic energy is 1000J. The change in kinetic energy is 15000J so the work against the motion is -15000J? If so then the displacement is 7.5m? Would the displacement be positive or negative?

Thanks for any help that you can provide
 
Last edited:
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You did it correct, but you are off by a factor of 0.1. So recheck your calculations.
 
Negative work implies that the force vector and displacement vector colinear with the force vector are in opposite directions. If the force acting on the car is directed to the left in the negative direction, then the displacement must be to the ____? Or from a practical sense, while the car, moving initially to the right, then starts to slow down, in which direction is it moving (displacing) during that slowing down period?
 
PhanthomJay said:
Negative work implies that the force vector and displacement vector colinear with the force vector are in opposite directions. If the force acting on the car is directed to the left in the negative direction, then the displacement must be to the ____? Or from a practical sense, while the car, moving initially to the right, then starts to slow down, in which direction is it moving (displacing) during that slowing down period?

If the force and displacement are in opposite directions, then the displacement must be towards the right, or am I tricking myself here because the object is accelerating to the left.
 
Red_CCF said:
If the force and displacement are in opposite directions, then the displacement must be towards the right, or am I tricking myself here because the object is accelerating to the left.
You are indeed correct!
 
Hootenanny said:
You are indeed correct!

Thanks! This was a confusing thing to wrap my head around because it's like pushing an object left but moving it right
 
Red_CCF said:
Thanks! This was a confusing thing to wrap my head around because it's like pushing an object left but moving it right
A good analogy to think about is when you're driving. If you press the brake pedal, then a force acts in the opposite direction of motion, slowing you down, but you are still moving forward.
 
rock.freak667 said:
You did it correct, but you are off by a factor of 0.1. So recheck your calculations.

I fixed my error. So the actual answer should be 7.5m towards the right?
 

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