Calculating distance, acceleration and time

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Homework Help Overview

The problem involves a truck maintaining a constant speed while approaching a car that begins to accelerate from rest at a traffic light. The scenario includes calculating how close the truck comes to the car as it accelerates.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the equations of motion for both the truck and the car, with some questioning the correctness of the expressions used for uniformly accelerated motion. There are also inquiries about the numerical values provided in the problem, particularly the truck's speed and the car's acceleration.

Discussion Status

Some participants have offered guidance on checking the equations and signs used in the calculations. There is recognition of potential confusion regarding the setup of the problem, and a few participants have expressed uncertainty about the values given, while others confirm that they have arrived at a correct result.

Contextual Notes

There are discussions about the unusual numerical values in the problem, with participants questioning whether they were copied correctly. The context suggests that the problem may have been perceived as lacking clarity or realism due to these values.

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Homework Statement


To save fuel, some truck drivers try to maintain a constant speed when possible. A truck traveling at 28.0 km/hr approaches a car stopped at the red light. When the truck is 110.7 meters from the car the light turns green and the car immediately begins to accelerate at 3.8 m/s2. How close does the truck come to the car assuming the truck does not slow down?

Homework Equations


Equations used:

V=V0+at
and r(t)=r0+v0t+0.5a2

The Attempt at a Solution


my attempt: http://imgur.com/RHuv2tq
RHuv2tq.jpg

I got an incorrect answer, what did i get wrong?
 
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Did I manage to get my reply across before the good spirit that watches over us took action ?

I asked you to check Dcar: that's not the expression for uniformly accelerated linear motion.

[edit] Oh, I see: you mixed them up. Nevertheless, answer's incorrect: you want to check what you do with the signs

By the way, the numerical values in this exercise are strange (truck speed very low wrt distance)
 
BvU said:
Did I manage to get my reply across before the good spirit that watches over us took action ?

I asked you to check Dcar: that's not the expression for uniformly accelerated linear motion.

[edit] Oh, I see: you mixed them up. Nevertheless, answer's incorrect: you want to check what you do with the signs

By the way, the numerical values in this exercise are strange (truck speed very low wrt distance)

Sorry, I didn't completely understand where the problem is?
 
It looks like you have the car and truck equations reversed. Also, I think your final equation would indicate that the vehicles are headed toward each other.
 
BvU said:
By the way, the numerical values in this exercise are strange (truck speed very low wrt distance)
You know, that's what I thought when I worked out the result - that the numbers were kind of strange. I was wondering if the acceleration number might have been wrong; it seems kind of high. But you're right that the truck's speed seems very low also. @agargento, please check that you copied all of the values correctly.
 
TomHart said:
You know, that's what I thought when I worked out the result - that the numbers were kind of strange. I was wondering if the acceleration number might have been wrong; it seems kind of high. But you're right that the truck's speed seems very low also. @agargento, please check that you copied all of the values correctly.

Hey, I got the correct result eventually, the numbers are correct. I've built an equation of their distance x(t) = 110.7 + 0.5 * 3.8 * t^2 -(28/3.6) * t and used the time I found to find the minimal distance, and it was correct.
 
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agargento said:
Hey, I got the correct result eventually, the numbers are correct.
Okay good. Glad to hear that. My personal opinion though is that the problem writers should add a little more drama and suspense. :)
 

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