Distance traveled during a head on collision

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SUMMARY

The discussion centers on the analysis of a head-on collision between a 1500 kg car traveling at 20 m/s and a 2400 kg truck moving at 12.5 m/s. The final velocities of both vehicles are concluded to be zero due to the conservation of momentum, expressed mathematically as 1500*(20) + 2400*(-12.5) = (1500 + 2400)*0. The average accelerations calculated are 40 m/s² for the car and 24 m/s² for the truck, leading to the conclusion that the car travels a greater distance of 5 m compared to the truck's 3.25 m during the collision. The discussion emphasizes the importance of understanding collision types (elastic vs. inelastic) and the role of momentum in determining post-collision behavior.

PREREQUISITES
  • Understanding of momentum conservation principles
  • Familiarity with basic kinematics equations
  • Knowledge of collision types: elastic and inelastic
  • Ability to calculate average acceleration
NEXT STEPS
  • Study the differences between elastic and inelastic collisions
  • Learn how to apply the conservation of momentum in various collision scenarios
  • Explore the concept of kinetic energy and its conservation in collisions
  • Investigate the effects of friction on vehicle motion post-collision
USEFUL FOR

Physics students, automotive engineers, and anyone interested in understanding the dynamics of vehicle collisions and the principles of momentum and energy conservation.

  • #31
phinds said:
1500*(20)+2400*(-12.5) = (1500+2400)*0

Makes it look like he is equating 20 - 12.5 with 0
Sorry, I still can't see how you can read it that way. Are you suggesting some interpretation of the asterisks other than multiplication?
 
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  • #32
haruspex said:
Sorry, I still can't see how you can read it that way. Are you suggesting some interpretation of the asterisks other than multiplication?
See post #29 for someone who had an immediate response identical to mine.
 
  • #33
phinds said:
See post #29 for someone who had an immediate response identical to mine.
Well, I can't see how that fits with what you wrote in post #30, and jbriggs' "physics" interpretation is how I read it. Mr. Krock took the equation m1v1i+m2v2i=(m1+m2)vf, plugged in the known values and found that vf must be 0. He then posted that fact in the form of a solved equation. I'm sure it was not intended to represent the logic by which he arrived at the result. As a way of illustrating where he was up to, I have no problem with it.
 
  • #34
haruspex said:
Well, I can't see how that fits with what you wrote in post #30,
You're right. Post #30 was an incorrect way to express my dismay at his intermediate result.

I'm sure it was not intended to represent the logic by which he arrived at the result.
Well, I'm not a mind reader. I was commenting on what he posted, not what he meant (although actually, I addressed that as well).

As a way of illustrating where he was up to, I have no problem with it.
Well, I do. Let's agree to disagree.
 
  • #35
phinds said:
You're right. Post #30 was an incorrect way to express my dismay at his intermediate result.

Well, I'm not a mind reader. I was commenting on what he posted, not what he meant (although actually, I addressed that as well).

Well, I do. Let's agree to disagree.
Ok, all good.
 
  • #36
It would help if we could get him to write the two equations.
To list the number of unknowns
To determine if there are enough equations to solve for the unknowns
To rearrange the equations to solve for the unknowns

Then to give the results for the three conditions 1) fully elastic. 2) inelastic 3) partially elastic.

Then to answer the question two ways. 1) for what was asked - distance travelled. Which is not knowable since no stopping forces were provided.

2) for what they probably wanted to ask - vehicle velocities.
 
  • #37
NickAtNight said:
It would help if we could get him to write the two equations.
To list the number of unknowns
To determine if there are enough equations to solve for the unknowns
To rearrange the equations to solve for the unknowns

Then to give the results for the three conditions 1) fully elastic. 2) inelastic 3) partially elastic.

Then to answer the question two ways. 1) for what was asked - distance travelled. Which is not knowable since no stopping forces were provided.

2) for what they probably wanted to ask - vehicle velocities.
No progress can be made at all until we are clear what is meant by the distance a vehicle travels during a collision. See post #25.
 

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