Calculating Distance Between Inner & Outer Triangles

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To calculate the distance between the sides of an inner equilateral triangle and an outer equilateral triangle, where the inner triangle has half the area of the outer triangle and is centered within it, the apothem method is appropriate. The distance can be determined by subtracting the apothem of the inner triangle from that of the outer triangle. The formula proposed, (1 - (1/sqrt(2))) * (outer triangle apothem), aligns with the calculations shared by others in the discussion. This approach is confirmed to yield the correct result for the distance measurement. Overall, the method and calculations presented are validated by participants in the thread.
strokebow
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Hi,

I have an equilateral triangle and I put another equilateral triangle within it. The inner triangle has exactly half of the area of the outer triangle. As well, the inner triangle is placed in the centre of the outer triangle i.e. they both have the same central point.

I want to measure the distance from one side of the inner triangle to the same side of the outer triangle.

My thinking is like so:
To find this distance, all i need is the apothem of the larger triangle minus the apothem of the smaller (inner) triangle.

What do you think?

I also calculated this to be: ( 1 - (1/sqrt(2)) ) * ( outer triangle apothem )

Do people get the same result as me? Or did I do something wrong? or make a bad assumption?

please help.

thanks
 
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Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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