Calculating Distance from Moon's Centre for Gravitational Field Change

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SUMMARY

The discussion focuses on calculating the distance from the center of the Moon based on gravitational force changes experienced by an astronaut. Initially, the astronaut experiences a gravitational force of 160 N at the Moon's surface and 40 N at a higher altitude. The relationship between gravitational force and distance is defined by the equation Fg ∝ 1/r². By recognizing that a reduction in gravitational force to one-fourth indicates a distance increase by a factor of two, the astronaut's new altitude can be determined in relation to the Moon's radius.

PREREQUISITES
  • Understanding of gravitational force and its relationship with distance
  • Familiarity with the formula Fg ∝ 1/r²
  • Basic knowledge of the Moon's radius
  • Concept of proportionality in physics
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  • Study gravitational force calculations in physics
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Students studying physics, educators teaching gravitational concepts, and anyone interested in celestial mechanics and gravitational field calculations.

Dark_Dragon
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An astronaut standing on the surface of the moon experiences a gravitational force of attraction of 160 N. He then moves away from the surface of the moon to an altitude where gravitational force is 40 N.

a) How far away from the centre of the moon is this new location in terms of the radius of the moon?

I know that Fg is proportional to 1/r^2

I don't know how to figure it out, can anyone point me in the right direction?

Thanks.
 
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Well, ask yourself two questions:

(1) How far away from the center of the moon is he when he is standing on the surface of the moon?

(2) How far away from the center of the moon would he need to be to reduce 1/r^2 to 1/4 of what it is on the surface of the moon?
 
aww man i didnt even think of it, thanks very much mate :)
 

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