Calculating Distance from Water Level to Stream Impact Point

[whereisccguys]

A tank is filled with water to a height H, 26 m. A hole is punched in one of the walls at a depth h = 6.50 m below the water surface (see the figure). What is the distance x from the base of the tank to the point at which the resulting stream strikes the floor?

i knoe the equation to find out the answer is x = 2\sqrt{h(H-h)} but i have really have no idea why, i knoe I'm suppose to use the kinematic equation of rho g h = 1/2 rho v^2 + rho g (H-h)

can any1 explain to me?

thanks

 

[Andrew Mason]

A tank is filled with water to a height H, 26 m. A hole is punched in one of the walls at a depth h = 6.50 m below the water surface (see the figure). What is the distance x from the base of the tank to the point at which the resulting stream strikes the floor?

i knoe the equation to find out the answer is x = 2\sqrt{h(H-h)} but i have really have no idea why, i knoe I'm suppose to use the kinematic equation of rho g h = 1/2 rho v^2 + rho g (H-h)

Use the Bernouilli equation to determine the speed, v, of the water. So you will know the horizontal speed and the distance above the ground. That is all you need to solve it. Hint: what is the time it takes to fall to the ground?

AM