Calculating distance given total work?

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Homework Help Overview

The discussion revolves around calculating distance based on total work done, specifically in the context of a sled being pulled with friction involved. The problem includes given values for total work, pulling force, frictional force, and an angle.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the equation for work and how to incorporate both the pulling force and frictional force into the calculation. There is an attempt to set up an equation based on the total work done, but the original poster notes an incorrect result. Questions arise about the direction of forces and the nature of work done by friction.

Discussion Status

Participants are actively exploring the problem, with some suggesting the need for a free body diagram to clarify forces. There is a focus on understanding the direction of the frictional force and its impact on work, indicating a productive line of questioning.

Contextual Notes

There is a mention of the angle associated with the sled and the forces involved, as well as the distinction between positive and negative work in relation to friction. The original poster's calculation appears to be based on an assumption that may need reevaluation.

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Homework Statement


The total work done is 2.42 * 10^4 J (work is from friction and person pulling a sled). The force of the person pulling is 135 N and the force of friction is 67 N. The angle on the sled is 48.

Homework Equations



W=f*d*cos0

The Attempt at a Solution



I was thinking I would need to do the Wt=f*dcos0 + f*dcos0

24200=135*d*cos 48 + 67*d*cos 180

I did this, but the answer was incorrect. the answer is 963 m.[/B]
 
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heythere1010 said:

Homework Statement


The total work done is 2.42 * 10^4 J (work is from friction and person pulling a sled). The force of the person pulling is 135 N and the force of friction is 67 N. The angle on the sled is 48.

Homework Equations



W=f*d*cos0

The Attempt at a Solution



I was thinking I would need to do the Wt=f*dcos0 + f*dcos0

24200=135*d*cos 48 + 67*d*cos 180

I did this, but the answer was incorrect. the answer is 963 m.[/B]
Start by drawing a free body diagram.
 
SammyS said:
Start by drawing a free body diagram.
Yes, the question has given that.
 
heythere1010 said:
Yes, the question has given that.
In what direction is the frictional force, relative to the direction of travel?
 
SammyS said:
In what direction is the frictional force, relative to the direction of travel?
The force of friction is west and the traveling direction is east.
 
heythere1010 said:
The force of friction is west and the traveling direction is east.
Then, does friction do positive work, or does it do negative work ?
 

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