How Much Work Is Done When Pulling a Sled at an Angle?

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Homework Help Overview

The problem involves calculating the work done when pulling a sled at an angle of 26.0° with a force of 74 N over a distance of 27 m. The context is set in a winter landscape, and the participants are exploring the implications of the angle and the force applied.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the calculation of work using the formula W = f x s x Cos, with some questioning the application of the cosine function in terms of degrees or radians. There is also a mention of considering the nature of the displacement in relation to the angle of pull.

Discussion Status

The discussion is ongoing, with participants providing feedback on the calculations and questioning the assumptions made regarding the angle and the displacement. Some guidance has been offered regarding common errors, but no consensus has been reached on the correct approach.

Contextual Notes

There is uncertainty about whether the sled is being pulled on flat ground or up an incline, which may affect the interpretation of the problem. Additionally, the original poster is struggling to understand the teacher's comments about displacements.

joesmith273
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Homework Statement


A sled is pulled across the barren winter landscape at an angle of 26.0° from the ground with a force of 74 N. If the sled is pulled over a distance of 27 m, how much work was done on the sled? Round your answer to two decimals

Homework Equations


W = f x s x Cos

The Attempt at a Solution


I calculated the force , 74, times 27 to get 1998. Then I multiplied 1998 by the cosine of 26 to get 1292.54 but it says that it's wrong. My teacher told me to think about the displacements but I don't get his meaning.
 
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joesmith273 said:
Then I multiplied 1998 by the cosine of 26 to get 1292.54

You multiplied by cosine of 26 what ? Radians or degrees?
 
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joesmith273 said:

Homework Statement


A sled is pulled across the barren winter landscape at an angle of 26.0° from the ground with a force of 74 N. If the sled is pulled over a distance of 27 m, how much work was done on the sled? Round your answer to two decimals

Homework Equations


W = f x s x Cos

The Attempt at a Solution


I calculated the force , 74, times 27 to get 1998. Then I multiplied 1998 by the cosine of 26 to get 1292.54 but it says that it's wrong. My teacher told me to think about the displacements but I don't get his meaning.
Is the sled being pulled over flat ground or up an incline?
 
Your method looks fine but see post #2.

Your teachers is talking about a common error but it's one that you didn't make.
 

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