Calculating Distance of Runners from Flagpole When Paths Cross

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Homework Help Overview

The problem involves two runners moving towards each other from different initial positions relative to a flagpole, with the goal of determining their distances from the flagpole at the moment their paths cross. The subject area includes concepts of relative motion and kinematics.

Discussion Character

  • Exploratory, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants discuss the setup of the problem, including drawing diagrams and considering the concept of displacement. There are attempts to calculate the time at which the runners meet and questions about the correctness of their calculations.

Discussion Status

The discussion is ongoing with participants sharing their calculations and expressing confusion about the results. Some have provided numerical answers, while others are questioning their approaches and seeking clarification on the setup.

Contextual Notes

There is mention of a potential misunderstanding regarding the expected format of the answer and the calculations involved. Participants are navigating through the problem with varying degrees of success and clarity.

alexistheman
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Runner A is initially 5.6 km west of a flagpole
and is running with a constant velocity of
8.7 km/h due east. Runner B is initially 4.2
km east of the flagpole and is running with a
constant velocity of 7.4 km/h due west.

How far are the runners from the flagpole
when their paths cross? Answer in units of
km.


How do i even start this, I am stuck.
 
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Drawing the scenario is always a good place to start.
R1------------------------------F-------------------------R2
Now you're looking for when R1 and R2 pass each other. That means what?
 
displacement by chance?
 
Like i drew it out, but when i do i still don't know how to set it all up. I am so stumped. :(
 
I got .3 KM but it says its wrong.. ugh
 
The runners will pass each other. This would happen after t hours. So that means that after t hours both runners will be at the same spot (not the same distance ran).
-Basically, at some time t, the two runners x position will be equal.
 
8.7 km/h + 7.4 km/h = 4.7 km + 5.6 km

16.1 km/h = 9.8 km

t = 9.8 km / 16.1

t=.608695652

8.7 * .608695652 = 5.29565213

5.6 - 5.29565213 = .30434782

your answer is .30434782 buddy
 
Hm, confusing. lol. I set it up and got 5.29 but ugh wouldn't it be .31
 
alexistheman said:
Hm, confusing. lol. I set it up and got 5.29 but ugh wouldn't it be .31
Why don't you post what you did.
 
  • #10
Ugh it wanted the full number, thanks ~.~
 
  • #11
it was operator and stupid website error lol
 
  • #12
happens..i had trouble on this one early tonight but i figured it out..
 
  • #13
well thanks man, heh.
 
  • #14
no prob.
 

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