Calculating Distance Traveled During Acceleration

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SUMMARY

The discussion focuses on calculating the distance traveled by a 9.0 kg object subjected to a net force of 6.6 N east, resulting in a uniform acceleration. The correct acceleration is determined to be 0.733 m/s² using Newton's second law (F=ma). The distance traveled during acceleration is calculated using the kinematic equation vf² = vi² + 2ad, leading to a distance of approximately 2 meters. The confusion arises from an incorrect answer key stating 6.1 m west, which contradicts the established direction of motion, as both force and velocity are directed east.

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  • Understanding of Newton's second law (F=ma)
  • Familiarity with kinematic equations, specifically vf² = vi² + 2ad
  • Basic knowledge of uniform acceleration
  • Ability to perform unit conversions and calculations
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  • Review Newton's laws of motion for deeper insights into force and acceleration
  • Study kinematic equations in detail, focusing on their applications in various scenarios
  • Explore the concept of vector direction in physics to clarify motion analysis
  • Practice solving similar problems involving forces and acceleration to reinforce understanding
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Homework Statement


A net force of 6.6 N east acts on a 9.0 kg object. If this object accelerates uniformly from rest to a velocity of 3.0 m/s east,

How far did the object travel while accelerating?

Homework Equations


F=ma
vf^2 = vi^2 + 2ad

The Attempt at a Solution


F=ma

a= f/m

a=6.6/9

a= 0.73333333333

vf^2 = vi^2 + 2ad

3 = 0 + 2(.733333)(d)

3= 1.467d

3/1.467 = about 2m
But the answer key says 6.1 m west. What did I do wrong and why is it west?
 
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Just a small glitch in math... you forgot to raise vf to the square. For direction just follow the path.
 
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It starts from rest. The force and velocity are both to the east. How can it move to the west?

But anyway the question only asks "How far did the object travel while accelerating?" so the direction isn't required?
 
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