- 41

- 1

**1. Homework Statement**

A 5.0kg block initally travelling at 11m/s moves up a 30degrees incline. A frictional force of 9.4N acts on the block as it moves up the incline. What maximum vertical height, h, will the block reach?

m = 5.0kg, vi = 11m/s, vf = 0m/s, Fr = 9.4N,

**2. Homework Equations**

vf^2=vi^2+2ad, Fnet=ma

**3. The Attempt at a Solution**

I tried finding the acceleration by doing F|| - Fr = ma [(5.0kg)(9.8)(sin30)-9.4N=(5.0kg)a]

when I found the acceleration, I used the equation vf^2=vi^2+2ad to find d, by assuming vf = 0m/s, and vi = 11m/s, which d would be = 20.033 m. After that I did 20.033m x sin30 which is 10m. The answer is supposed to be 4.5m