Calculating Electric Field Strength and Direction for a Negative Charge

[dragon-kazooie]

I think I have this correct, could someone please verify? I compared answers with a friend who got 2.0 x 10⁶ N/C to the left, and I can't figure out how they got that answer, so I'm hoping mine is right...

1. Homework Statement
A negative charge of 3.5 × 10–8 C experiences a force of 0.070 N to the right in an electric field. What is the field magnitude and direction?

Homework Equations

Electric field strength = f / q

The Attempt at a Solution

Electric field strength = f / q

Electric field strength = 0.070 N / 3.5x10^-8

Electric field strength = 2x106 N/C To the left

 

[BvU]

Funny, $2\times 10^6$ N/C to the left looks to me to be the same as $2\times 10^6$ N/C to the left . Or do you mean you found $2\times 106 = 212$ N/C to the left ?

 

[dragon-kazooie]

Funny, $2\times 10^6$ N/C to the left looks to me to be the same as $2\times 10^6$ N/C to the left . Or do you mean you found $2\times 106 = 212$ N/C to the left ?

Oh goodness, I got myself all mixed up. I should have written "I compared answers with a friend who got 0.02 N/C to the left, and I can't figure out how they got that answer, so I'm hoping mine is right..."

Thank you for asking for clarification. I'm sorry that I didn't proof read my question closely enough!

 

[berkeman]

Electric field strength = 2x106 N/C To the left

Once you fix your exponent, this looks correct to me.

a friend who got 0.02 N/C

Not sure how your friend could have gotten this. Maybe ask them to show your their work?

 

[dragon-kazooie]

Thank you!