Calculating Electric Potential at Sphere and Shell

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In summary, we have a conducting sphere with a radius of 0.31 m and a net charge of +4 µC, surrounded by a thin, non-conducting spherical shell with a radius of 0.86 m and a net charge of +1.5 µC. The electric potential at infinity is zero. We are asked to calculate the electric potential at various points: 0.4 m outside the thin shell, at the thin shell, halfway between the surface of the sphere and the surrounding shell, at the surface of the sphere, and at the center of the sphere. Using Gauss' Law, we can solve for the electric potential at each point and get the following answers: a) 9*10^
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jromega3
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Homework Statement



A conducting sphere with radius a = 0.31 m has a net charge Qa = +4 µC. A thin, non-conducting spherical shell of radius b = 0.86 m surrounds the sphere and is concentric with it. This shell has a net charge Qb = +1.5 µC distributed uniformly over its surface. The electric potential at infinity is zero.

(a) Calculate the electric potential at a radial distance of 0.4 m outside of the thin shell.
(b) Calculate the potential at the thin shell.
(c) Find the electric potential mid-way between the surface of the sphere and the surrounding shell.
(d) Find the potential at the surface of the sphere.
(e) Find the potential at the center of the sphere.

Homework Equations





The Attempt at a Solution



These are driving me crazy. My work gives me the following answers...
a) 9*10^9 (4*10^-6+1.5*10^-6/1.57)
b) 9*10^9(4*10^-6+1.5*10^-6/0.215)
c) 9*10^9(4*10^-6/0.585+1.5*10^-6/0.86)
d) 9*10^9(4*10^-6/0.31+1.5*10^-6/0.86)
e) 9*10^9(4*10^-6/0.31+1.5*10^-6)

which aren't right when I'm typing them in.
 
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As a scientist, it is important to double-check your calculations and make sure your units are correct. It appears that your calculations may be correct, but your units may be causing issues when you are inputting them into the system. Make sure to use the correct units for charge (Coulombs) and distance (meters) when solving for electric potential. Additionally, it is important to note that the electric potential at infinity is zero, so you can use that information to check your solutions. If you are still having trouble, it may be helpful to review the equations and units for calculating electric potential.
 

FAQ: Calculating Electric Potential at Sphere and Shell

1. How do you calculate the electric potential at a point near a charged sphere?

To calculate the electric potential at a point near a charged sphere, you can use the equation V = kQ/r, where V is the electric potential, k is the Coulomb's constant, Q is the charge of the sphere, and r is the distance from the center of the sphere to the point. This equation assumes that the point is outside the sphere and the sphere is a point charge.

2. What is the electric potential inside a charged spherical shell?

Inside a charged spherical shell, the electric potential is constant and equal to the potential at the surface of the shell. This is because the electric field inside a conductor is zero, so there is no change in potential as you move inside the shell.

3. How do you calculate the electric potential at a point near a charged spherical shell?

To calculate the electric potential at a point near a charged spherical shell, you can use the equation V = kQ/r, where V is the electric potential, k is the Coulomb's constant, Q is the charge of the shell, and r is the distance from the center of the shell to the point. This equation assumes that the point is outside the shell and the shell is a point charge.

4. Can the electric potential at a point near a charged sphere be negative?

Yes, the electric potential at a point near a charged sphere can be negative. This usually occurs when the point is inside the sphere, as the potential decreases as you move closer to the center of the sphere.

5. How does the electric potential at a point near a charged sphere or shell change as the distance from the sphere or shell increases?

The electric potential at a point near a charged sphere or shell decreases as the distance from the sphere or shell increases. This is because the electric potential is inversely proportional to the distance from the charged object, according to the equation V = kQ/r.

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