- #1

Monoxdifly

MHB

- 284

- 0

What I have done:

100 = 60sin\(\displaystyle \alpha\)t and 10 = 60sin\(\displaystyle \alpha\)t - \(\displaystyle \frac{1}{2}(10)t^2\)

\(\displaystyle t=\frac{5cos\alpha}{3}\) and \(\displaystyle 10=t(60sin\alpha)-t)\)

Dunno what to do from here on.