Calculating Energy Changes in a Crane Lifting a Beam: A Scientific Analysis

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SUMMARY

This discussion focuses on calculating energy changes involved in a crane lifting a beam with a mass of 1000 kg. The crane's petrol engine burns fuel that releases 1 MJ of chemical potential energy, with 85% lost to the air. Key calculations include determining the fuel cost for raising the beam, the change in total energy in terms of height (h), and the average power output of the engine over a 55-second period. The equations used include the energy balance equation (ΔE = W + Q), where W represents work done and Q represents heat transfer.

PREREQUISITES
  • Understanding of energy conservation principles
  • Familiarity with potential and kinetic energy calculations
  • Knowledge of calorific value and fuel density
  • Basic grasp of power output calculations
NEXT STEPS
  • Calculate the fuel cost using the calorific value of the fuel and its density
  • Determine the change in gravitational potential energy as a function of height (h)
  • Analyze the energy changes in the crane's engine and superstructure
  • Compute average power output using the work-energy principle over the given time frame
USEFUL FOR

Students in physics or engineering, particularly those studying mechanics and energy transformations, as well as professionals involved in crane operations and energy efficiency analysis.

Alaa Wahbi
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please please please please help me with this question.

Hi every one,

i'm gettin crazy trying to solve this question, please do help if u could, i would really appreciate that.

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** A crane uses its petrol engine to lift a beam of mass 1000 kg by height h. The fuel burned loses 1 MJ (million J) of chemical potential energy, 85% of this being transferred by heating to the air. The internal energy of the crane's engine increases by 4.0×10000 J, while that of the crane's superstructure and the beam is unchanged. The crane's superstructure ( not engine of fuel) increases in graviational potential energy by 10000 J. Everything is at rest before and after. Assume all transfer by working out of the crane is used to lift the beam.

(a) The calorific value of the fuel is 43 MJ/kg, its density is 737 kg m(to power -3) and it costs 90p (pens) per liter (there are 1000 liter in 1 m to power 3). What was the fuel cost of raising the beam?
(b) What is the change in total energy of the beam in terms of h?
(c) Consider the energy changes of the whole crane (fuel + engine + superstructure) to find the height h.
(d) Consider the energy changes of the engine (including fuel). If the whole process takes 55 seconds, find the average power output by working of the engine.


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please help me.
 
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Welcome to the PF. As per the guidelines that you just agreed to, you must show your own work so far in order for us to help you. What kind of energy and work equations have you been using so far on these problems?
 
Hi berkeman,

thanks for ur replay, however I am really sorry that i couldn't reach any point of myself work. Because i don't understand the question properly, maybe coz the language is a problem for me, I'm not a native speaker!

I need some hints or any thing like that, I would use equations like:

(Delta) E= W + Q

so,

Kinetic Energy + Potential Energy + Internal Energy = W + Q

where W is the work.
Q is the amount of energy transferred by heating.


would these equations be correct ?
 

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