Am i correct in getting a low value?

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SUMMARY

The discussion focuses on calculating the fuel cost associated with raising a 103 kg beam using a crane powered by a petrol engine. The fuel burned releases 1 MJ of chemical potential energy, with 85% lost to heating the air. The crane's engine experiences an increase in internal energy of 4.0×104 J, while the gravitational potential energy of the crane's superstructure increases by 104 J. The calorific value of the fuel is 43 MJ kg−1, and the cost of the fuel is 90p per litre, leading to a specific calculation for the fuel cost of raising the beam.

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madglover
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A crane uses its petrol engine to lift a beam of mass 103 kg by height
h. The fuel burned loses 1 MJ (106 J) of chemical potential energy, 85%
of this being transferred by heating to the air. The internal energy of the
crane’s engine increases by 4.0×104 J, while that of the crane’s superstructure
and the beam is unchanged. The crane’s superstructure (not engine or fuel)
increases in gravitational potential energy by 104 J. Everything is at rest
before and after. Assume all transfer by working out of the crane is used to
lift the beam.
(a) [10 marks] The calorific value of the fuel is 43 MJ kg−1, its density is 737
kg m−3 and it costs 90p per litre (there are 1000 litres in 1 m3). What was
the fuel cost of raising the beam?
 
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I tried to apply lots of the basic energy conservations laws but get stuck when approaching an answer making me very depressed. Sympathy work well on here?
 
Lets see your working so far and where you are are stuck.
 

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